A deuteron is accelerated from rest through a 10 kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 3 T. What is the radius of the resulting circular path? %3D -27 -19 (deuteron: m= 3.3 x 10 kg, q = 1.6 x 10 C) Select one: а. 10.1 mm b. 5.0 mm c. 6.8 mm d. 12.7 mm

Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter14: Nuclear Physics Applications
Section: Chapter Questions
Problem 32P
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A deuteron is accelerated from rest through a 10 kV
potential difference and then moves perpendicularly to
a uniform magnetic field with B = 3 T. What is the
radius of the resulting circular path?
%3D
-27
(deuteron: m= 3.3 x 10
kg, q = 1.6 x 10
-19
C)
Select one:
a. 10.1 mm
b. 5.0 mm
c. 6.8 mm
d. 12.7 mm
Transcribed Image Text:A deuteron is accelerated from rest through a 10 kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 3 T. What is the radius of the resulting circular path? %3D -27 (deuteron: m= 3.3 x 10 kg, q = 1.6 x 10 -19 C) Select one: a. 10.1 mm b. 5.0 mm c. 6.8 mm d. 12.7 mm
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