A deuteron is accelerated from rest through a 10 kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 2 T. What is the radius of the resulting circular path? -27 -19 (deuteron: m= 3.3 x 10 kg, q = 1.6 x 10 C) Select one: a. 6.8 mm b. 5.0 mm c. 12.7 mm d. 10.1 mm

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter30: Nuclear Physics
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A deuteron is accelerated from rest through a 10 kV
potential difference and then moves perpendicularly to a
uniform magnetic field with B = 2 T. What is the radius of the
resulting circular path?
-27
(deuteron: m= 3.3 x 10" kg, q = 1.6 x 10
-19
Select one:
a. 6.8 mm
b. 5.0 mm
c. 12.7 mm
d. 10.1 mm
Transcribed Image Text:A deuteron is accelerated from rest through a 10 kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 2 T. What is the radius of the resulting circular path? -27 (deuteron: m= 3.3 x 10" kg, q = 1.6 x 10 -19 Select one: a. 6.8 mm b. 5.0 mm c. 12.7 mm d. 10.1 mm
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