I need help with part C, please show all work thank you!!! 8. The following data was collected for the reaction: A 2B + C[A]5.934.843.75Time (sec)50100a) Determine the order of A.3.75-4.84-1.09- 0.0218CAJ3-CAJ250%3D+3-t2100-50[AJS -[AJI4.84-5.93-1.09= -0.0218%3D%3D5050 -0The order of A IS zerob) Calculate the rate law constant, k.rate = k = ACA]%3D= - 0,0218Atk= - 0.0218c) Calculate the [A] after 215 seconds

a) Determine the order of A. -1.09 CAJ3-CAJ2 3.75-4.84 %3D 100-50 50 +3-t2 -1.09 =4.84-5.93 %3D +ュ-+」 50 - 0 50 The order b) Calculate the rate law constant, k. rate = k = 4CA] %3D = - 0,0218 At k= - 0.0218 c) Calculate the [A] after 215 seconds

a) Determine the order of A. -1.09 CAJ3-CAJ2 3.75-4.84 %3D 100-50 50 +3-t2 -1.09 =4.84-5.93 %3D +ュ-+」 50 - 0 50 The order b) Calculate the rate law constant, k. rate = k = 4CA] %3D = - 0,0218 At k= - 0.0218 c) Calculate the [A] after 215 seconds

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Screen reader description: The Ordinary Phases of Carbon Dioxide. Pressure (Pa) 10 to the power of 0 to 10 up to 10 to the power of 8 on Y-axis. Temperature in Kelvins 0 to 700 on X-axis. Curved line up from 105 K at 10 to the power of 0 Pa up to 200 K and 10 to the power of 6 Pa. The line forks here. There is an almost vertical line up to 10 to the power of 8 Pa, and a line that goes diagonally up and to the right to 325 K and 10 to the power of 7 Pa. To the left of the fork is "Solid". To the right of the fork is "Gas". In between the lines of the fork is "Liquid". End of image. The tempterature closest to the triple point is: 0 K 100 K 200 K 300 K 400 K 500 K 600 K 700 K 100 Pa 101 Pa 102 Pa 103 Pa 104 Pa 105 Pa 106 Pa 107 Pa