Suppose a pendulum of length L meters makes an angle of 0 radians with the vertical, as in the figure. It can be shown that as afunction of time, 0 satisfies the differential equationLd20sin 0 = 0,Ldt2where g = 9.8 m/s? is the acceleration due to gravity. For 0 near zero we can use the linear approximation sin(0) - 0 to get alinear differential equationd200 = 0.Ldt?Use the linear differential equation to answer the following questions.(a) Determine the equation of motion for a pendulum of length 1.5 meters having initial angle 0.2 radians and initial angulardo= 0.3 radians per second.dtvelocity0(t)radians(b) What is the period of the pendulum? That is, what is the time for one swing back and forth?Period =seconds

Given, L=1.5m θ=0.2 raddθdt=0.3 rad Given, the equation of motion is, d2θdt2+gL=0Solve this…

Answered: (a) Determine the equation of motion…

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(a) Determine the equation of motion for a pendulum of length 1.5 meters having initial angle 0.2 radians and initial angular de velocity dt 0.3 radians per second. 0(t) = radians (b) What is the period of the pendulum? That is, what is the time for one swing back and forth? Period = seconds