a) Determine the cumulative distribution function of photoresist thickness. b) Determine the proportion of wafers that exceeds 0.2125 micrometers in photoresist thickness. c) What thickness is exceeded by 10% of the wafers? d) Determine the mean and variance of photoresist thickness.
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- Let the height data (105)represent sample. Use an appropriate statistical test to check whether the population mean is different from 170 cm.Use α = 0.05.Also, write a substantive conclusion and explanation. Use an appropriate graph to check if data is normally distributed. Do it in R commander.6. A sample of 5 fathers and their eldest sons gave the following data about their weight in Kgs. Father (x): 65 60 67 63 74 Son (y): 49 45 57 40 60 CS Scanned with CamScannerTo determine if their 14 oz filling machine is properly adjusted, Harvey Soft Drinks has decided to use an X-Chart which uses the range to estimate the variability in the sample. J. Answer How to enter your answ Table Step 1 of 7: What is the Center Line of the control chart? Round your answer to three decimal places. Control Chart Period 1 2 3 4 5 6 7 8 9 10 11 Select the Copy Table button to copy all values. To select an entire row or column, either click on the row or column header or use the Shift and arrow keys. To find the average of the selected cells, select the Average Values button. Copy Table Average Values The average of the selected cell(s) is 14.000. Copy Value Sample Mean Sample Range 14.0060 0.04 0.04 0.04 0.10 0.08 0.09 0.07 0.05 0.05 0.06 0.07 obs1 obs2 obs3 obs4 obs5 14.00 13.99 14.03 14.01 14.00 14.02 14.05 14.05 14.01 14.04 14.0340 14.02 14.01 14.05 14.04 14.02 14.0280 14.04 13.97 14.05 13.95 14.00 14.0020 13.96 14.01 14.00 14.04 14.02 14.0060 13.96 14.00 14.00…
- I need help for figuring out how to explain parts a and b.3.) A population has a mean of 300 and a variance of 80. If we get 160 samples from this population, what wili be the mean and standard deviation of the sampling distribution of sample mean? A.) Hg = 300 and og =0.53 B.) µg = 300 and og =0.71 C.) µg = 300 and og =6.32 D.) µg = 300 and og =80 %3D %3D7. Assume the following normal distribution to represent the plasma cholesterol values of randomly selected individuals in mmol/L. o = 0.5 5.2 a. Convert 4.15 mmol/L to z score. b. Convert 6.55 mmol/L to z score. c. Convert 4.39 mmol/L to z score. d. What value in mmol/L corresponds to a z score of 1.38? e. What value in mmol/L corresponds to a z score of -0.44? f. Find P(X s 5.89) g. Find P(X 2 4.59) h. Find P(4.39 sX< 5.60) i. Find x such that P(X 2 x) = 0.0359 j. Find x such that P(4.98 s Xs x) = 0.6598
- Periodically, the county Water Department tests the drinking water of homeowners for contaminants such as lead and copper. The lead and copper levels in water specimens collected in 1998 for a sample of 10 residents of a subdevelopement of the county are shown below. lead (μμg/L) copper (mg/L) 4.4 0.643 2.4 0.57 1.5 0.46 2.6 0.895 5.9 0.2 3.4 0.54 3.8 0.245 1.6 0.583 5.7 0.769 1.7 0.215 (a) Construct a 9999% confidence interval for the mean lead level in water specimans of the subdevelopment. ≤μ≤A uniform distribution has endpoints 4 and 18. What is the 90th percentile, reporting to one decimal place?A boat capsized and sank in a lake. Based on an assumption of a mean weight of 142 lb, the boat was rated to carry 60 passengers (so the load limit was 8,520 lb). After the boat sank, the assumed mean weight for similar boats was changed from 142 lb to 171 lb. Complete parts a and b below. a. Assume that a similar boat is loaded with 60 passengers, and assume that the weights of people are normally distributed with a mean of 178.5 lb and a standard deviation of 36.9 lb. Find the probability that the boat is overloaded because the 60 passengers have a mean weight greater than 142 lb. The probability is 1.000. (Round to four decimal places as needed.) C.. b. The boat was later rated to carry only 13 passengers, and the load limit was changed to 2,223 lb. Find the probability that the boat is overloaded because the mean weight of the passengers is greater than 171 (so that their total weight is greater than the maximum capacity of 2,223 lb). The probability is. (Round to four decimal…
- VE Review 29 View Alignment Wrap Text Merge & Center - Bookl- Microsoft Excel Answer General ling %9 68. Number B The mean yield for one-acre plot is 662 kilos with a s.d. 32 kilos. Assuming normal distribution, how many one-acre plots in a batch of 1000 plots would you expect to have yield (i) over 700 kilos, (ii) below 650 kilos, (iii) what is the lowest yield of the best 100 plots? Cell Conditional Format Formatting as Table Styles - Styles hp C InseSuppose the lengths of human pregnancies are normally distributed with µ = 266 days and o= 16 days. Complete parts (a) and (b) below. (Type integers or decimals.) A. The proportion of human pregnancies that last less than B. The proportion of human pregnancies that last more than days is days is Provide a second interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) O A. The probability that a randomly selected human pregnancy lasts less than B. The probability that a randomly selected human pregnancy lasts more than (b) The figure to the right represents the normal curve with µ = 266 days and o = 16 days. The area between x = 280 and x = 295 is 0.1558. Provide two interpretations of this area. days is days is Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or…Calculate the coefficient of variation of a distribution with: 2*f = 110 and *² · f = 1235 n = 10, %3D %3D 1.596 75.496 15.2% 25.3%