A) Determine the boundary limits of the following regions in spaces. The region D₁ bounded by the planes x + 2y + 3z = 6 and the coordinate planes. The region D₂ bounded by the cylinders y = x² and y = 4 - x², and the planes x + 2y + z = 1 and x + y + z = 1. The region D3 bounded by the cone z² = x² + y² and the parabola z = 2-x² - y² The region D4 in the first octant bounded by the cylinder - x² + y² = 4, the paraboloid z = 8 - x2 - y² and the planes x = y, z = 0, and x = 0. B) Calculate the following integrals JJJ. dV, y dV JJJ.* xy dV, [11. D4 dV,

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Just calculate the integral of region D3 and D4 ( B part). [The boundary limits of D3 and D4 are already given in the image below]
A) Determine the boundary limits of the following regions in spaces.
The region D₁ bounded by the planes x + 2y + 3z: 6 and the
coordinate planes.
The region D2₂ bounded by the cylinders y = x² and y = 4 - x², and
the planes x + 2y + z = 1 and x + y + z = 1.
The region D3 bounded by the cone z² = x² + y2 and the parabola
z=2-x² - y²
The region D4 in the first octant bounded by the cylinder
x² + y² = 4, the paraboloid z = 8 - x² - y² and the planes x = y,
z = 0, and x = = 0.
B) Calculate the following integrals
JJJ.
dV,
III yov [][
J.
xy dV
JJJ.
dV₁
Transcribed Image Text:A) Determine the boundary limits of the following regions in spaces. The region D₁ bounded by the planes x + 2y + 3z: 6 and the coordinate planes. The region D2₂ bounded by the cylinders y = x² and y = 4 - x², and the planes x + 2y + z = 1 and x + y + z = 1. The region D3 bounded by the cone z² = x² + y2 and the parabola z=2-x² - y² The region D4 in the first octant bounded by the cylinder x² + y² = 4, the paraboloid z = 8 - x² - y² and the planes x = y, z = 0, and x = = 0. B) Calculate the following integrals JJJ. dV, III yov [][ J. xy dV JJJ. dV₁
18:49 G
←
Step2
b)
(3
Here
(4)
=> Z²
So
22= x2+y2
= x² + y² = (2-be²+ y²)) ²
y varies from
x varies from
Putting x=y
y
2
u = (2-4)²
4 = 4-44+4²
4²-$4+4=0
(4-4) (4-1)=0
4=1,4
x² + y² = 1₂4
but from 2 = 2-(x² + y²), x² + y² ≤ 2
Hence x² + y² = 1 (This gives the limits for x,y)
Here z varies from √₂z+yz to
2-x²-y2.
√1-x² to
√1-x2
-1
1
|||
in
2 =2-x²-y²
O
(Let u= x² + y²)
х2+у?
4
x²+x²=4
2x²=4
z varies from
0 to
8-x²-y²
x
varies from y to √4-yz (from cylinded
varies
from
to
√2
31%
x² = 2 = x = √₂
⇒ y = √2
√x
<
Do
Transcribed Image Text:18:49 G ← Step2 b) (3 Here (4) => Z² So 22= x2+y2 = x² + y² = (2-be²+ y²)) ² y varies from x varies from Putting x=y y 2 u = (2-4)² 4 = 4-44+4² 4²-$4+4=0 (4-4) (4-1)=0 4=1,4 x² + y² = 1₂4 but from 2 = 2-(x² + y²), x² + y² ≤ 2 Hence x² + y² = 1 (This gives the limits for x,y) Here z varies from √₂z+yz to 2-x²-y2. √1-x² to √1-x2 -1 1 ||| in 2 =2-x²-y² O (Let u= x² + y²) х2+у? 4 x²+x²=4 2x²=4 z varies from 0 to 8-x²-y² x varies from y to √4-yz (from cylinded varies from to √2 31% x² = 2 = x = √₂ ⇒ y = √2 √x < Do
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