(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1- p) 2 10 B. Not normal because ns0.05N and np(1 – p) < 10 C. Approximately normal because ns0.05N and np(1- p) < 10 O D. Approximately normal because ns0.05N and np(1- p) 2 10 Determine the mean of the sampling distribution of p. | (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. | (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 300 adults, more than 22% do not own a credit card? The probability is . (Round to four decimal places as needed.)
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1- p) 2 10 B. Not normal because ns0.05N and np(1 – p) < 10 C. Approximately normal because ns0.05N and np(1- p) < 10 O D. Approximately normal because ns0.05N and np(1- p) 2 10 Determine the mean of the sampling distribution of p. | (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. | (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 300 adults, more than 22% do not own a credit card? The probability is . (Round to four decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question 7: a, b, c, and d.

Transcribed Image Text:According to a survey in a country, 19% of adults do not own a credit card. Suppose a simple random sample of 300 adults is obtained. Complete parts (a) through (d) below.
**(a)** Describe the sampling distribution of \( \hat{p} \), the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of \( \hat{p} \) below.
- **A.** Not normal because \( n \leq 0.05N \) and \( np(1 - p) \geq 10 \)
- **B.** Not normal because \( n \leq 0.05N \) and \( np(1 - p) < 10 \)
- **C.** Approximately normal because \( n \leq 0.05N \) and \( np(1 - p) < 10 \)
- **D.** Approximately normal because \( n \leq 0.05N \) and \( np(1 - p) \geq 10 \)
Determine the mean of the sampling distribution of \( \hat{p} \).
\( \mu_{\hat{p}} = \) \_\_\_ (Round to two decimal places as needed.)
Determine the standard deviation of the sampling distribution of \( \hat{p} \).
\( \sigma_{\hat{p}} = \) \_\_\_ (Round to three decimal places as needed.)
**(b)** What is the probability that in a random sample of 300 adults, more than 22% do not own a credit card?
The probability is \_\_\_. (Round to four decimal places as needed.)

Transcribed Image Text:**Transcription of Probability and Statistical Analysis**
1. **Random Sampling of Adults Without Credit Cards:**
- If we obtain 100 different random samples of 300 adults, we would expect a certain number of samples to result in more than 22% not owning a credit card.
- **Instruction:** Round to the nearest integer as needed.
2. **Calculation of Probability:**
- What is the probability that in a random sample of 300 adults, the percentage of those who do not own a credit card falls between 17% and 22%?
- **Answer Field:** The probability is _____.
- **Instruction:** Round to four decimal places as needed.
3. **Interpretation of Probability:**
- If 100 different random samples of 300 adults were obtained, one would expect a certain number of samples to fall between 17% and 22% not owning a credit card.
- **Instruction:** Round to the nearest integer as needed.
4. **Evaluation of Unusual Results:**
- Query: Would it be unusual for a random sample of 300 adults to result in 51 or fewer who do not own a credit card? Why?
- **Answer Options:**
- **A:** The result is not unusual because the probability that \(\hat{p}\) is less than or equal to the sample proportion is _____, which is greater than 5%.
- **B:** The result is not unusual because the probability that \(\hat{p}\) is less than or equal to the sample proportion is _____, which is less than 5%.
- **C:** The result is unusual because the probability that \(\hat{p}\) is less than or equal to the sample proportion is _____, which is less than 5%.
- **D:** The result is unusual because the probability that \(\hat{p}\) is less than or equal to the sample proportion is _____, which is greater than 5%.
- **Instruction:** Round to four decimal places as needed.
**Note:** Replace blanks and placeholders with the actual computed numbers to complete the transcription based on statistical calculations.
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