(a) Describe the hybridization of the central atom of a molecule with a see-saw shape. (b) Describe the hybridization of the central atom of a molecule with a trigonal planar shape. (c) Describe the hybridization of the central atom of a molecule with a trigonal bipyramidal shape.

(a) Describe the hybridization of the central atom of a molecule with a see-saw shape. (b) Describe the hybridization of the central atom of a molecule with a trigonal planar shape. (c) Describe the hybridization of the central atom of a molecule with a trigonal bipyramidal shape.

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter10: Molecular Structure And Bonding Theories

Section: Chapter Questions

Problem 10.108QE: Aspirin, or acetylsalicylic acid, has the formula C9H8O4 and the skeleton structure (a) Complete the...

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Aspirin, or acetylsalicylic acid, has the formula C9H8O4 and the skeleton structure (a) Complete the Lewis structure and give the number of bonds and bonds in aspirin. (b) What is the hybridization about the CO2H carbon atom (colored blue)? (c) What is the hybridization about the carbon atom in the benzene-like ring that is bonded to an oxygen atom (colored red)? Also, what is the hybridization of the oxygen atom bonded to this carbon atom?
H2CO molecules (a) use orbital hybridization theory to determine the molecular shape of h2co. (b) what bonds are formed between the c and o atoms in formaldehyde molecules?
In hydrogen isocyanide molecules (HCN), both carbon (C: 1s^2 2s^2 2p^2 ) and nitrogen (N: 1s^2 2s^2 2p^3 ) atoms undergo sp hybridization. (a) Use Orbital Hybridization theory to determine the molecular shape of HCN molecules. (b) Explain how the C atom binds to the N atom in HCN molecules.
Butadiene, C4H6, is a planar molecule that has the followingcarbon–carbon bond lengths: (a) Predict the bond angles around each of the carbon atoms and sketch the molecule. (b) From left to right, what is the hybridization of each carbon atom in butadiene? (c) The middle C—C bond length in butadiene (1.48 Å) is a little shorter than the average C—C single bond length (1.54 Å). Does this imply that the middle C—C bond in butadiene is weaker or stronger than the average C—C single bond? (d) Based on your answer for part (c), discuss what additional aspects of bonding in butadiene might support the shorter middle C—C bond.
The structure of caffeine is shown below. (a) Complete the Lewis structure. (b) How many pi bonds are present in caffeine? How many sigma bonds? (c) Identify the hybridization of the carbon atoms. (d) What is the value of the O-C-N angle?
A useful solvent that will dissolve salts as well as organic compounds is the compound acetonitrile, H3CCN. It is present in paint strippers.(a) Write the Lewis structure for acetonitrile, and indicate the direction of the dipole moment in the molecule.(b) Identify the hybrid orbitals used by the carbon atoms in the molecule to form σ bonds.(c) Describe the atomic orbitals that form the π bonds in the molecule. Note that it is not necessary to hybridize the nitrogen atom.
Consider the reaction BF3 + NH3 -> F3B-NH3 (a) Describe the changes in hybridization of the B and N atoms as a result of this reaction. (b) Describe the shapes of all the reactant molecules with their bond angles. (c) Draw the overall shape of the product molecule and identify the bond angles around B and N atoms. (d) What is the name of the bond between B and N. (e)Describe the bonding orbitals that make the B and F, B and N & N and H bonds in the product molecule.
(a) Write a single Lewis structure for SO3 , and determine the hybridization at the S atom. (b) Are there other equivalent Lewis structures for the molecule? (c) Would you expect SO3 to exhibit delocalized π bonding?
For each of the following molecule: (i) draw the correct Lewis structure; (ii) determine the molecular geometry and the type of hybridization on the central atom, and (iii) predict whether the molecule is polar or nonpolar. (a) BrCl5
On your drawings indicate the hybridization of (a) the sulfur atom in a sulfuric acid molecule. (c) the oxygen atoms in an acetic acid molecule. (b) the oxygen atoms in a sulfuric acid molecule. (d) the carbon atoms in an acetic acid molecule.
In ozone, O3, the two oxygen atoms on the ends of the molecule are equivalent to one another. (a)What is the best choice of hybridization scheme for the atoms of ozone? (b) For one of the resonance forms of ozone, which of the orbitals are used to make bonds and which are used to hold nonbonding pairs of electrons? (c) Which of the orbitals can be used to delocalize the π electrons? (d) How many electrons are delocalized in the π system of ozone?
The molecule 2-butene, C4H8, can undergo a geometricchange called cis-trans isomerization:As discussed in the “Chemistry and Life” box on the chemistryof vision, such transformations can be induced bylight and are the key to human vision. (a) What is the hybridizationat the two central carbon atoms of 2-butene?(b) The isomerization occurs by rotation about the centralC¬C bond. With reference to Figure 9.29, explainwhy the p bond between the two central carbon atoms isdestroyed halfway through the rotation from cis- to trans-2-butene. (c) Based on average bond enthalpies (Table 8.3),how much energy per molecule must be supplied to breakthe C¬C p bond? (d) What is the longest wavelength oflight that will provide photons of sufficient energy to breakthe C¬C p bond and cause the isomerization? (e) Is thewavelength in your answer to part (d) in the visible portionof the electromagnetic spectrum? Comment on the importanceof this result for human vision.