(a) Derive the relativistic length contraction using the Lorentz transformation. (b) Derive the formula for time dilation using the inverse Lorentz transformation.
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A: Measurements of lengths as well as time intervals are affected by relative motion.


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- The proper length of one spaceship is three times that of another. The two spaceships are traveling in the same direction and, while both are passing overhead, an Earth observer measures the two spaceships to have the same length. If the slower spaceship has a speed of 0.354c with respect to Earth, determine the speed of the faster spaceship. (Give your answer to at least 3 significant figures.) |cAn observer measures a spacecraft’s length to be exactly half of its rest length. a) What is the speed of the ship relative to the observer’s frame of reference? b) By what factor do the spaceship’s clocks run slow relative to clocks in the observer’s frame?A way to measure the length of an object moving at known(relativistic) speed is to measure the interval between the passage of referencepoints past an observer. By considering the times at which the leading and trailling ends of a moving rod pass an observer, and applying Lorentz transformations,show that the same expression for length contraction as : L=yo-1L' is obtained,draw a spacetime diagram if needed
- 12. (a) A particle is traveling through the Earth's atmosphere at a speed of 0.750c. To an earth bound observer, the distance it travels is 2.5km. How far does the particle travel in the particle's frame of reference? (b) Calculate the momentum of an electron traveling at a speed 0.985c? The rest mass of the electron is 9.11 X 10-31 kg.A spaceship from another galaxy passes over the solar system directly above a radial line from the sunto the Earth. (We measure the distance between the Earth and the Sun to be 1.496 x 1011 m.) Anobserver standing on the Earth measures that the spaceship is approaching at 0.800c. The Earth-basedobserver also measures that it takes the spaceship 625 seconds to travel from the sun to Earth. Ignorethe relative motion of the Sun and Earth in this problem – their relative speed is only 0.001c, negligiblysmall compared to 0.800c.a) According to a scientist in the spaceship, the Earth-Sun distance is: ______8.9 x 10 ^10__________________b) According to a scientist in the spaceship, the time it takes her to travel the Earth-Sun distance is:_________374 s _______________c) What is the ratio of the kinetic energy to rest energy of the spaceship? KE/ER = _______0.667__________d) As the spaceship passed over the Sun, the alien scientist launched a probe toward Earth, traveling at0.200c relative to…A car is moving relative to a pedestrian with a Lorentz factor of 1.45. With the length of the car being 5.7m according to the pedestrian, what's the length according to the driver of the car (he's moving at the same speed of the car) ?
- Consider a general equation for the ratio the relativistic length to the proper length. Find an algebraic expression for v/c in terms of, ΔL/ΔLo Show the algebraic form of the equation that you apply and the final final expression.At relativistic speeds near that of light, the half-life of an unstable particle moving at high speed is longer than when it is at rest. an object is longer when moving than when it is stationary. O light emitted by a moving source moves at the same speed with the same frequency. effects precede causes in some inertial frames. lengths and times only appear different and have no effect on other measurable quantities.An alarm clock is set to sound in 10.0 = h. Att 0, the clock is placed in a spaceship moving with a speed of 0.736 c (relative to Earth). What distance, as determined by an Earth observer, does the spaceship travel before the alarm clock sounds? (Hint: Keep track of your units!) answer in m
- An object with a rest mass of 1.5 kg is moving at a speed of 0.91c. (a) Determine the relativistic momentum of the object. (b) Determine the total relativistic energy, in joules, of the object according to a stationary observer.Suppose a cosmic ray colliding with a nucleus in the Earth's upper atmosphere produces a muon that has speed v = 0.99c. The muon then travels at constant speed and lives 1.5 μs as measured in the muon's frame of reference. (You can imagine this as the muon's internal clock.)Randomized Variablesv = 0.99 ct = 1.5 μs Part (a) How many kilometers does the muon travel according to an Earth-bound observer? Part (b) How many kilometers of the Earth pass by as viewed by an observer moving with the muon? Base your calculation on its speed relative to the Earth and its lifetime (proper time).Calculate the ratio of the relativistic kinetic energy to the classical energy kinetic energy for an electron (mass = 9.109x10^-31 kg) moving with constant speed of 0.75c.