Can you please tell me the big O notation for this function? HAFAAAFAdef func_two (stack1, stack2):result = TrueAnum_ops = 5# If the stacks are the same size, then we can do this comparisonif stack1.get_size() == stack2.get_size():# We create an array to hold the data from one stack, and an array to hold data from the othertmp_data = []tmp_stack = Stack()num_ops += 5# We could use an array for each one if we wished, but for simplicity in returning, we choose the stack# Iterate through stack2, storing all values in tmp_datawhile stack2.get_size() > 0:tmp_data.append(stack2.pop())num_ops += 5# Iterate through stack1, searching tmp_data for each itemnum_ops += 3while stack1.get_size() > 0:else:item = stack1.pop()num_ops += 3 + len(tmp_data) |if item in tmp_data:tmp_stack.push(item)num_ops += 1else:result = Falsestack1.push(item)num_ops += 2breaknum_ops += 3# Rebuild both stacksnum_ops += 3while tmp_stack.get_size() > 0:stack1.push(tmp_stack.pop())num_ops += 5num_ops += 3for i in range (len (tmp_data) - 1, -1, -1):stack2.push(tmp_data[i])num_ops += 3result = Falsenum_ops += 1print("This call took %d operations" % num_ops)return result

Complexity: Complexity is a concept that is used to describe the behavior of systems that have many…

A def func_two (stack1, stack2): result = True num_ops = 5 # If the stacks are the same size, then we can do this comparison if stack1.get_size() == stack2.get_size(): # We create an array to hold the data from one stack, and an array to hold data from the other tmp_data = [] tmp_stack = Stack() num_ops += 5 # We could use an array for each one if we wished, but for simplicity in returning, we choose the stack # Iterate through stack2, storing all values in tmp_data while stack2.get_size() > 0: A A A tmp_data.append(stack2.pop()) num_ops += 5 # Iterate through stack1, searching tmp_data for each item num_ops += 3 while stack1.get_size() > 0: item stack1.pop() num_ops += 3 + len(tmp_data) | else: if item in tmp_data: tmp_stack.push(item) num_ops += 1 else: result = False stack1.push(item) num_ops += 2 break num_ops += 3 # Rebuild both stacks num_ops += 3 while tmp_stack.get_size() > 0: stack1.push(tmp_stack.pop()) num_ops += 5 num_ops += 3 for i in range (len (tmp_data) - 1, -1, -1): stack2.push(tmp_data[i]) num_ops += 3 result = False num_ops += 1 print("This call took %d operations" % num_ops) return result

A def func_two (stack1, stack2): result = True num_ops = 5 # If the stacks are the same size, then we can do this comparison if stack1.get_size() == stack2.get_size(): # We create an array to hold the data from one stack, and an array to hold data from the other tmp_data = [] tmp_stack = Stack() num_ops += 5 # We could use an array for each one if we wished, but for simplicity in returning, we choose the stack # Iterate through stack2, storing all values in tmp_data while stack2.get_size() > 0: A A A tmp_data.append(stack2.pop()) num_ops += 5 # Iterate through stack1, searching tmp_data for each item num_ops += 3 while stack1.get_size() > 0: item stack1.pop() num_ops += 3 + len(tmp_data) | else: if item in tmp_data: tmp_stack.push(item) num_ops += 1 else: result = False stack1.push(item) num_ops += 2 break num_ops += 3 # Rebuild both stacks num_ops += 3 while tmp_stack.get_size() > 0: stack1.push(tmp_stack.pop()) num_ops += 5 num_ops += 3 for i in range (len (tmp_data) - 1, -1, -1): stack2.push(tmp_data[i]) num_ops += 3 result = False num_ops += 1 print("This call took %d operations" % num_ops) return result

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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