Find the the P value ### Problem StatementA data set includes data from student evaluations of courses. The summary statistics are as follows:- Sample size ($ n $) = 93- Sample mean ($ \bar{x} $) = 4.11- Sample standard deviation ($ s $) = 0.68Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.### Hypothesis Options**What are the null and alternative hypotheses?**- A. $ H_0: \mu = 4.25 $ $ H_1: \mu < 4.25 $- B. $ H_0: \mu = 4.25 $ $ H_1: \mu \neq 4.25 $- C. $ H_0: \mu \neq 4.25 $ $ H_1: \mu = 4.25 $- D. $ H_0: \mu = 4.25 $ $ H_1: \mu > 4.25 $The selected answer is $ \mathbf{B} $: $ H_0: \mu = 4.25 $ and $ H_1: \mu \neq 4.25 $.### Instructions1. **Determine the test statistic:** Round to two decimal places as needed.2. **Enter your answer:** Provide the test statistic in the answer box and click "Check Answer."### VisualsThere are no graphs or diagrams in the image.**Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.

Name: Find the the P value ### Problem StatementA data set includes data fro
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Description: Find the the P value ### Problem StatementA data set includes data from student evaluations of courses. The summary statistics are as follows:- Sample size ($ n $) = 93- Sample mean ($ \bar{x} $) = 4.11- Sample standard deviation ($ s $) = 0.68

The sample mean is 4.11 and the standard deviation is 0.68.

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A data set includes data from student evaluations of courses. The summary statistics are n= 93, x- 4.11, s 0.68. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion th addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 B. Ho: u=4.25 H:H<4.25 H: u#4.25 O C. Ho: H#4.25 D. Ho : μ 4.25 H:H=4.25 H1: µ>4.25 Determine the test statistic. (Round to two decimal places as needed.)

A data set includes data from student evaluations of courses. The summary statistics are n= 93, x- 4.11, s 0.68. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion th addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 B. Ho: u=4.25 H:H<4.25 H: u#4.25 O C. Ho: H#4.25 D. Ho : μ 4.25 H:H=4.25 H1: µ>4.25 Determine the test statistic. (Round to two decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

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Question

Find the the P value

### Problem Statement

A data set includes data from student evaluations of courses. The summary statistics are as follows:
- Sample size ($ n $) = 93
- Sample mean ($ \bar{x} $) = 4.11
- Sample standard deviation ($ s $) = 0.68

Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.

### Hypothesis Options

**What are the null and alternative hypotheses?**
- A. $ H_0: \mu = 4.25 $ $ H_1: \mu < 4.25 $
- B. $ H_0: \mu = 4.25 $ $ H_1: \mu \neq 4.25 $
- C. $ H_0: \mu \neq 4.25 $ $ H_1: \mu = 4.25 $
- D. $ H_0: \mu = 4.25 $ $ H_1: \mu > 4.25 $

The selected answer is $ \mathbf{B} $: $ H_0: \mu = 4.25 $ and $ H_1: \mu \neq 4.25 $.

### Instructions

1. **Determine the test statistic:**
Round to two decimal places as needed.

2. **Enter your answer:**
Provide the test statistic in the answer box and click "Check Answer."

### Visuals

There are no graphs or diagrams in the image.

**Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.

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