A data set includes data from student evaluations of courses. The summary statistics are n= 93, x- 4.11, s 0.68. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion th addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 B. Ho: u=4.25 H:H<4.25 H: u#4.25 O C. Ho: H#4.25 D. Ho : μ 4.25 H:H=4.25 H1: µ>4.25 Determine the test statistic. (Round to two decimal places as needed.)
A data set includes data from student evaluations of courses. The summary statistics are n= 93, x- 4.11, s 0.68. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion th addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 B. Ho: u=4.25 H:H<4.25 H: u#4.25 O C. Ho: H#4.25 D. Ho : μ 4.25 H:H=4.25 H1: µ>4.25 Determine the test statistic. (Round to two decimal places as needed.)
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Find the the P value
![### Problem Statement
A data set includes data from student evaluations of courses. The summary statistics are as follows:
- Sample size (\( n \)) = 93
- Sample mean (\( \bar{x} \)) = 4.11
- Sample standard deviation (\( s \)) = 0.68
Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
### Hypothesis Options
**What are the null and alternative hypotheses?**
- A. \( H_0: \mu = 4.25 \) \( H_1: \mu < 4.25 \)
- B. \( H_0: \mu = 4.25 \) \( H_1: \mu \neq 4.25 \)
- C. \( H_0: \mu \neq 4.25 \) \( H_1: \mu = 4.25 \)
- D. \( H_0: \mu = 4.25 \) \( H_1: \mu > 4.25 \)
The selected answer is \( \mathbf{B} \): \( H_0: \mu = 4.25 \) and \( H_1: \mu \neq 4.25 \).
### Instructions
1. **Determine the test statistic:**
Round to two decimal places as needed.
2. **Enter your answer:**
Provide the test statistic in the answer box and click "Check Answer."
### Visuals
There are no graphs or diagrams in the image.
**Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2734b2e5-bfdc-4698-b164-7fb7c5253f73%2F89a773e3-f60e-47c3-9db5-8151f4683a86%2Ftm92g9s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A data set includes data from student evaluations of courses. The summary statistics are as follows:
- Sample size (\( n \)) = 93
- Sample mean (\( \bar{x} \)) = 4.11
- Sample standard deviation (\( s \)) = 0.68
Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
### Hypothesis Options
**What are the null and alternative hypotheses?**
- A. \( H_0: \mu = 4.25 \) \( H_1: \mu < 4.25 \)
- B. \( H_0: \mu = 4.25 \) \( H_1: \mu \neq 4.25 \)
- C. \( H_0: \mu \neq 4.25 \) \( H_1: \mu = 4.25 \)
- D. \( H_0: \mu = 4.25 \) \( H_1: \mu > 4.25 \)
The selected answer is \( \mathbf{B} \): \( H_0: \mu = 4.25 \) and \( H_1: \mu \neq 4.25 \).
### Instructions
1. **Determine the test statistic:**
Round to two decimal places as needed.
2. **Enter your answer:**
Provide the test statistic in the answer box and click "Check Answer."
### Visuals
There are no graphs or diagrams in the image.
**Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.
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