A data set includes data from student evaluations of courses. The summary statistics are n= 93, x- 4.11, s 0.68. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion th addresses the original claim. What are the null and alternative hypotheses? O A. Ho: H=4.25 B. Ho: u=4.25 H:H<4.25 H: u#4.25 O C. Ho: H#4.25 D. Ho : μ 4.25 H:H=4.25 H1: µ>4.25 Determine the test statistic. (Round to two decimal places as needed.)

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Question

Find the the P value 

### Problem Statement

A data set includes data from student evaluations of courses. The summary statistics are as follows:
- Sample size (\( n \)) = 93
- Sample mean (\( \bar{x} \)) = 4.11
- Sample standard deviation (\( s \)) = 0.68

Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.

### Hypothesis Options

**What are the null and alternative hypotheses?**
- A. \( H_0: \mu = 4.25 \)    \( H_1: \mu < 4.25 \)
- B. \( H_0: \mu = 4.25 \)    \( H_1: \mu \neq 4.25 \)
- C. \( H_0: \mu \neq 4.25 \) \( H_1: \mu = 4.25 \)
- D. \( H_0: \mu = 4.25 \)    \( H_1: \mu > 4.25 \)

The selected answer is \( \mathbf{B} \): \( H_0: \mu = 4.25 \) and \( H_1: \mu \neq 4.25 \).

### Instructions

1. **Determine the test statistic:**  
   Round to two decimal places as needed.

2. **Enter your answer:**  
   Provide the test statistic in the answer box and click "Check Answer."

### Visuals

There are no graphs or diagrams in the image.

**Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.
Transcribed Image Text:### Problem Statement A data set includes data from student evaluations of courses. The summary statistics are as follows: - Sample size (\( n \)) = 93 - Sample mean (\( \bar{x} \)) = 4.11 - Sample standard deviation (\( s \)) = 0.68 Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. ### Hypothesis Options **What are the null and alternative hypotheses?** - A. \( H_0: \mu = 4.25 \) \( H_1: \mu < 4.25 \) - B. \( H_0: \mu = 4.25 \) \( H_1: \mu \neq 4.25 \) - C. \( H_0: \mu \neq 4.25 \) \( H_1: \mu = 4.25 \) - D. \( H_0: \mu = 4.25 \) \( H_1: \mu > 4.25 \) The selected answer is \( \mathbf{B} \): \( H_0: \mu = 4.25 \) and \( H_1: \mu \neq 4.25 \). ### Instructions 1. **Determine the test statistic:** Round to two decimal places as needed. 2. **Enter your answer:** Provide the test statistic in the answer box and click "Check Answer." ### Visuals There are no graphs or diagrams in the image. **Note:** The task is to complete the hypothesis testing by calculating the test statistic and evaluating it against the significance level to draw a conclusion about the population mean.
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