A data set about speed dating includes "like" ratings of male dates made by the female dates. Thesummary statistics are n=15, x=137.33, s=24.12. Use a 0.01 significance level to test the claim thatthe population mean of such ratings is greater than 110. Assume that a simple random sample hasbeen selected. Identify the null and alternative hypotheses, test statistic, P-value, and state thefinal conclusion that addresses the original claim..The Hypotheses TestHo:µ = 110H1:Choose one of these A:u > 110B: µ < 110C: µ #110Test statisticChoose one of these(A) t = 4.39; (B) z == 4.39P value< s.f. = 0.10( reject or do not reject)%3D(Round to three decimal places as needed. )

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Answered: A data set about speed dating includes…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that Dietitians recently recommended a 400 cal per meal and take her children of the age of the data set. To see if both groups adhere to the guideline follow the steps to develop and test a statistical hypothesis. Test to see if us groups means are different from 400 calories. You have two data sets so you'll be completing the process twice. Use 0.05 as a level of significance and make sure to report any important statistic with your results (e.g., mean of each group, standard deviation of each group, test stastistic (are you using t or z?), rejection region and p value). Data: Children Participated Children Did Not Participate 435.16 414.61 338.99 503.46 488.73 425.22 590.28 288.77 582.59 184 635.21 299.73 249.86 350.65 441.66 394.94 572.43 261.55 357.78 295.28 396.79 139.69 298.38 462.78 282.99 179.59 368.51 301.75 388.59 436.58 256.32 371.39 408.82 469.02 424.94 378.09 477.96 287.31 428.74 448.55 432.52 332.64 428.27…
A sample of 63 stocks traded on the NYSE that day showed that 22 went up. You are conducting a study to see if the proportion of stocks that went up is significantly more than 0.3. You use a significance level of a = 0.05. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... O less than (or equal to) a Ogreater than a This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... OThere is sufficient evidence to warrant rejection of the claim that the proportion of stocks that went up is more than 0.3. O There is not sufficient evidence to warrant rejection of the claim that the proportion of stocks that went up is more than 0.3. The sample data support the claim that the proportion of stocks that went up is more than 0.3. There is not…
Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than17 μg/g. Assume that the sample is a simple random sample. 13.5, 22.5, 7.5, 17, 22, 15.5, 9, 15.5, 5, 6 Determine the test statistics.
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 98.46, y = 99.4, r=0.883, P-value = 0.000, and y=-14.65 +1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 101? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
Use a 0.01 significance level to test the claim that the mean amount of time spent watching television by women is smaller than the mean amount of time spent watching television by men.
A hypertension trial is mounted and 12 participants are randomly assigned to receive either a new treatment or a placebo. Each participant takes the assigned medication and their systolic blood pressure (SBP) is recorded after 6 months on the assigned treatment. The data are as follows. Placebo New Treatment 132 114 143 119 148 121 144 124 155 126 160 128 Is there a difference in mean SBP between treatments? Run the test at a 5% level of significance. Give each of the following to receive full credit : 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic ; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
A data set includes data from student evaluations of courses. The summary statistics are nequals=8585, x overbarxequals=3.423.42, sequals=0.540.54. Use a 0.010.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.503.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Data were collected from 400 patients in the US about their estrogen level. Out of the 400, 35 patient have abnormal estrogen levels. On a national level, 8 % of patients have abnormal estrogen level. Researchers want to know the sample proportion differs from the national level. 5% is used for significance. Give the Ho and Ha. The appropriate test. Decision rule. Test calculations. Conclusion with comparison to alpha or critical value. I think this is a two tailed test. Use a one sample t- test. I think the null is rejected. t (40-1) = (400-35) / (.05 divided by sqrt 31) This is where I get stuck.
The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a sample mean of 131.2 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.. a. Ho: μ= 132 mg vs. H₁: b. He: ≤132 mg vs. H₁: c. He: ≥132 mg vs. H₁: Oa Ob Oc (b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Test statistic 132 mg >132 mg <132 mg (c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim? Decision Rule: Reject Ho
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x= 100.1, y = 98.3, r=0.961, P-value = 0.000, and y = - 18.02 + 1.16x, where x represents the IQ score of the wife. Find the best predicted value of y given that the wife has an IQ of 100? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is (Round to two decimal places as needed.)
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 102.13, y = 101.35, r= 0.927, P-value = 0.000, and y = 2.05 + 0.97x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 103? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r The best predicted value of y is (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r a = 0.05 a = 0.01 NOTE: To test Ho: p=0 Jagainst H,: p#0, reject H, lif the absolute value of r is greater than the critical value in the table. 4. 0.950 0.990 0.878 0.959 6 0.811 0.917 0.754 0.875 8. 0.707 0.834 0.666 0.632 0.602 9 0.798 10 0.765 11 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 0.468 0.456 18 0.590 19 0.575…

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