A daredevil drove his motorcycle up an incline at 40 degree angle with the horizontal and drove off the end of the incline at 22 m/s, 12 m above the ground. How fast was him (magnitude of total velocity) when he landed?

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Physics Problem: Projectile Motion**

A daredevil drove his motorcycle up an incline at a 40-degree angle with the horizontal and drove off the end of the incline at 22 m/s, 12 meters above the ground. How fast was he (magnitude of total velocity) when he landed?

---

**Solution Explanation:**

To solve this problem, we need to apply the principles of projectile motion. Here's a step-by-step guide on how to calculate the magnitude of the velocity when the daredevil lands.

1. **Decompose the Initial Velocity:**
   - **Horizontal Component (Vx):**
     \[
     Vx = V \cos(\theta) = 22 \, m/s \cdot \cos(40^{\circ})
     \]
     \[
     Vx \approx 16.85 \, m/s
     \]

   - **Vertical Component (Vy):**
     \[
     Vy = V \sin(\theta) = 22 \, m/s \cdot \sin(40^{\circ})
     \]
     \[
     Vy \approx 14.14 \, m/s
     \]

2. **Calculate the Time of Flight (t):**
   - Using the equation for vertical displacement under gravity:
     \[
     y = Vy \cdot t + \frac{1}{2}gt^2
     \]
     Here, \( y = -12 \, m \) (since the daredevil lands 12 meters below the takeoff point), and \( g = 9.8 \, m/s^2 \). Rearrange and solve the quadratic equation for \( t \):
     \[
     -12 = 14.14 \, t - 4.9 \, t^2
     \]

     Solving this quadratic equation gives \( t \approx 3.67 \, s \).

3. **Calculate the Final Vertical Velocity (Vy_final) just before landing:**
   - Using the equation of motion:
     \[
     Vy_{final} = Vy + gt
     \]
     \[
     Vy_{final} = 14.14 - 9.8 \times 3.67
     \]
     \[
     Vy_{final} \approx -21.76 \, m/s
     \]

4. **Calculate the Magnitude of the Total Velocity:**
   -
Transcribed Image Text:**Physics Problem: Projectile Motion** A daredevil drove his motorcycle up an incline at a 40-degree angle with the horizontal and drove off the end of the incline at 22 m/s, 12 meters above the ground. How fast was he (magnitude of total velocity) when he landed? --- **Solution Explanation:** To solve this problem, we need to apply the principles of projectile motion. Here's a step-by-step guide on how to calculate the magnitude of the velocity when the daredevil lands. 1. **Decompose the Initial Velocity:** - **Horizontal Component (Vx):** \[ Vx = V \cos(\theta) = 22 \, m/s \cdot \cos(40^{\circ}) \] \[ Vx \approx 16.85 \, m/s \] - **Vertical Component (Vy):** \[ Vy = V \sin(\theta) = 22 \, m/s \cdot \sin(40^{\circ}) \] \[ Vy \approx 14.14 \, m/s \] 2. **Calculate the Time of Flight (t):** - Using the equation for vertical displacement under gravity: \[ y = Vy \cdot t + \frac{1}{2}gt^2 \] Here, \( y = -12 \, m \) (since the daredevil lands 12 meters below the takeoff point), and \( g = 9.8 \, m/s^2 \). Rearrange and solve the quadratic equation for \( t \): \[ -12 = 14.14 \, t - 4.9 \, t^2 \] Solving this quadratic equation gives \( t \approx 3.67 \, s \). 3. **Calculate the Final Vertical Velocity (Vy_final) just before landing:** - Using the equation of motion: \[ Vy_{final} = Vy + gt \] \[ Vy_{final} = 14.14 - 9.8 \times 3.67 \] \[ Vy_{final} \approx -21.76 \, m/s \] 4. **Calculate the Magnitude of the Total Velocity:** -
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