A dam has a semi-circular gate at the bottom that is 4 m in diameter. The dam is 12 m high and filled with water 10 m deep. Find the hydrostatic forces against the gate. Use pg = 9810 N/m³. O 196200x N O 107 – 8/3 N 52320x N O 19620 (107 – 8/3) N
A dam has a semi-circular gate at the bottom that is 4 m in diameter. The dam is 12 m high and filled with water 10 m deep. Find the hydrostatic forces against the gate. Use pg = 9810 N/m³. O 196200x N O 107 – 8/3 N 52320x N O 19620 (107 – 8/3) N
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.6: The Three-dimensional Coordinate System
Problem 40E: For the sphers x-12+y+22+z-42=36 and x2+y2+z2=64, find the ratio of their a surface areas. b...
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![A dam has a semi-circular gate at the bottom that is 4 m in
diameter. The dam is 12 m high and filled with water 10 m
deep. Find the hydrostatic forces against the gate. Use
pg = 9810 N/m³.
O 196200x N
107 – 8/3 N
O 523207 N
019620 (10т — 8/3) N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F766e9f36-76bb-4307-8526-11192cdbf562%2F7c42331d-0094-4aca-8f4f-d0014de299d2%2Ft1uaov7_processed.png&w=3840&q=75)
Transcribed Image Text:A dam has a semi-circular gate at the bottom that is 4 m in
diameter. The dam is 12 m high and filled with water 10 m
deep. Find the hydrostatic forces against the gate. Use
pg = 9810 N/m³.
O 196200x N
107 – 8/3 N
O 523207 N
019620 (10т — 8/3) N
![Set-up the integral in solving the volume of the solid formed
by revolving the region bounded by the curves a = 2y? and
1 = y +1 about the line y = -2, using a horizontal
element.
Ov = 2# J', (y + 2) (1 – y²) dy
O v = 27 f", (2 – y) (1 + y²) dy
Ov = 27 , (-2) (v-1-) dz
Ov=2= f; (2) (VE – vz-1) dz
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F766e9f36-76bb-4307-8526-11192cdbf562%2F7c42331d-0094-4aca-8f4f-d0014de299d2%2Fmg0zts_processed.png&w=3840&q=75)
Transcribed Image Text:Set-up the integral in solving the volume of the solid formed
by revolving the region bounded by the curves a = 2y? and
1 = y +1 about the line y = -2, using a horizontal
element.
Ov = 2# J', (y + 2) (1 – y²) dy
O v = 27 f", (2 – y) (1 + y²) dy
Ov = 27 , (-2) (v-1-) dz
Ov=2= f; (2) (VE – vz-1) dz
%3D
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