A cylinder containing 119.9 cubic centimeter of gas at a pressure of 238 kPa when its temperature is 595 K. Given that its volume is unchanged when the pressure was increased by a factor of 2.7, Determine the new Temperature of the gas (In Kelvin). Note: Your answer must be in Kelvin, however, do not include the unit, just enter the magnitude that corresponds to the final volume in Kelvin. Round your answer to 2 decimal points
Energy transfer
The flow of energy from one region to another region is referred to as energy transfer. Since energy is quantitative; it must be transferred to a body or a material to work or to heat the system.
Molar Specific Heat
Heat capacity is the amount of heat energy absorbed or released by a chemical substance per the change in temperature of that substance. The change in heat is also called enthalpy. The SI unit of heat capacity is Joules per Kelvin, which is (J K-1)
Thermal Properties of Matter
Thermal energy is described as one of the form of heat energy which flows from one body of higher temperature to the other with the lower temperature when these two bodies are placed in contact to each other. Heat is described as the form of energy which is transferred between the two systems or in between the systems and their surrounding by the virtue of difference in temperature. Calorimetry is that branch of science which helps in measuring the changes which are taking place in the heat energy of a given body.
![### Gas Law Problem
A cylinder containing 119.9 cubic centimeters of gas at a pressure of 238 kPa when its temperature is 595 K. Given that its volume is unchanged when the pressure was increased by a factor of 2.7, determine the new temperature of the gas (in Kelvin).
**Note:** Your answer must be in Kelvin. However, do not include the unit, just enter the magnitude that corresponds to the final temperature in Kelvin. Round your answer to 2 decimal points.
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**Solution Explanation:**
To solve for the new temperature of the gas, we can use the ideal gas law and the relation between pressure, volume, and temperature:
\[ PV = nRT \]
Since the volume and the amount of gas are constant, we can use the combined gas law:
\[ \frac{P_1}{T_1} = \frac{P_2}{T_2} \]
Given:
- Initial pressure, \( P_1 = 238 \, \text{kPa} \)
- Initial temperature, \( T_1 = 595 \, \text{K} \)
- The pressure is increased by a factor of 2.7, so \( P_2 = 238 \times 2.7 \, \text{kPa} \)
We need to find the new temperature \( T_2 \). Rearrange the equation to solve for \( T_2 \):
\[ T_2 = \frac{P_2 \times T_1}{P_1} \]
Substitute the given values:
\[ T_2 = \frac{(238 \times 2.7) \times 595}{238} \]
Simplify to find \( T_2 \):
\[ T_2 = 2.7 \times 595 \]
\[ T_2 = 1606.50 \]
Therefore, the new temperature of the gas is **1606.50 K** (rounded to 2 decimal points).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f1e4f7e-3ee3-4328-9071-c5dd7af83341%2F2a25d682-34e4-4354-9711-669b4f5ca77b%2Fgbb5soa_processed.jpeg&w=3840&q=75)
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