A cyclist accelerates from rest at a rate of 1.00 m/s². How fast will a point at the top of the rim of the tire (diameter = 68.0 cm) be moving after 2.25 s? [Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest-see Fig. 8–57.] v = ? FIGURE 8–57 a = 1.00 m/s² Problem 79. This point on tire at rest momentarily

College Physics
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A cyclist accelerates from rest at a rate of 1.00 m/s². How
fast will a point at the top of the rim of the tire
(diameter = 68.0 cm) be moving after 2.25 s? [Hint: At
any moment, the lowest point on the tire is in contact with
the ground and is at rest-see Fig. 8–57.]
v = ?
FIGURE 8–57
a = 1.00 m/s²
Problem 79.
This point on tire
at rest momentarily
Transcribed Image Text:A cyclist accelerates from rest at a rate of 1.00 m/s². How fast will a point at the top of the rim of the tire (diameter = 68.0 cm) be moving after 2.25 s? [Hint: At any moment, the lowest point on the tire is in contact with the ground and is at rest-see Fig. 8–57.] v = ? FIGURE 8–57 a = 1.00 m/s² Problem 79. This point on tire at rest momentarily
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