A current of strength I=1A flows through the copper wire. The wire consists of two straight parts between points A(1,2,3)cm and B(1,3,2)cm and between points B and C(2,1,3)cm. The wire is located in a homogeneous magnetic field of induction B=1T. a) If the total force on the wire is 0, calculate the direction of the magnetic field. b) If we rotate the direction of the magnetic field so that the total force on the wire is the largest, calculate the maximum possible force on the wire.

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A: Given: B=0.450 T (East)q=-3.10*10-18 Cv=0.30 cm/s =0.3*10-2 m/s (straight down in B field)

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A: 0.26 NExplanation:

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A: Given:-        From the data                      r = 6.19×10-11 mv = 2.47×106 m/sB = 6.04×10-3T