A current of intensity "I" circulates through a closed wire of arbitrary shape in the presence of a uniform magnetic field B. Show explicitly that the total force that acts on the part of the wire from a point "a" to another point "b", is given by: F = IlxB where " " is the vector from "a" to "b".
A current of intensity "I" circulates through a closed wire of arbitrary shape in the presence of a uniform magnetic field B. Show explicitly that the total force that acts on the part of the wire from a point "a" to another point "b", is given by: F = IlxB where " " is the vector from "a" to "b".
Related questions
Question
Transcribed Image Text:A current of intensity "I" circulates through a closed wire of arbitrary shape in the presence of a
uniform magnetic field B. Show explicitly that the total force that acts on the part of the wire from
a point "a" to another point "b", is given by: F = IlxB where " " is the vector from "a" to "b".
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 1 images
