A curling iron is plugged into an outlet at time t = 0. Its temperature T in degrees Fahrenheit, assumed to be a continuous function that is strictly increasing and concave down on 0st≤ 120, is given at various times (in seconds) in the following table. Answer parts (a) through (c) below. t (seconds) T(t) (°F) 0 70 120 1 (a) Approximate 120 context of this problem. 0 20 130 44 200 1 60 239 T(t) dt in three ways: using a left Riemann sum, a right Riemann sum, and the Trapezoid Rule. Interpret the value of 1 120 120 120 Using a left Riemann sum, S 0 (Type an integer or decimal rounded to three decimal places as needed.) 90 110 120 311 354 375 T(t) dt. 120 0 T(t) dt in the
A curling iron is plugged into an outlet at time t = 0. Its temperature T in degrees Fahrenheit, assumed to be a continuous function that is strictly increasing and concave down on 0st≤ 120, is given at various times (in seconds) in the following table. Answer parts (a) through (c) below. t (seconds) T(t) (°F) 0 70 120 1 (a) Approximate 120 context of this problem. 0 20 130 44 200 1 60 239 T(t) dt in three ways: using a left Riemann sum, a right Riemann sum, and the Trapezoid Rule. Interpret the value of 1 120 120 120 Using a left Riemann sum, S 0 (Type an integer or decimal rounded to three decimal places as needed.) 90 110 120 311 354 375 T(t) dt. 120 0 T(t) dt in the
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A curling iron is plugged into an outlet at time t = 0. Its temperature T in degrees Fahrenheit, assumed to be a continuous function that is strictly increasing and concave
down on 0 st≤ 120, is given at various times (in seconds) in the following table. Answer parts (a) through (c) below.
t (seconds)
T(t) (°F)
0
70
1
20
130
(a) Approximate
120
context of this problem.
44
200
120
120
S
T(t) dt in three ways: using a left Riemann sum, a right Riemann sum, and the Trapezoid Rule. Interpret the value of S T(t) dt in the
0
0
1
120
60
239
120
Using a left Riemann sum,
S
0
(Type an integer or decimal rounded to three decimal places as needed.)
120
90 110
311 354 375
T(t) dt
1
120
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