A cruise boat travels 12 miles downstream in 2 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream. OA. 4.002 mph OB. 6 mph O C. 1.998 mph OD. 10.002 mph
A cruise boat travels 12 miles downstream in 2 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream. OA. 4.002 mph OB. 6 mph O C. 1.998 mph OD. 10.002 mph
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![### Problem Statement
A cruise boat travels 12 miles downstream in 2 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream.
### Options
- **A.** 4.002 mph
- **B.** 6 mph
- **C.** 1.998 mph
- **D.** 10.002 mph
### Explanation
Given:
- Downstream distance: 12 miles
- Downstream time: 2 hours
- Upstream time: 6 hours
We can calculate the speeds as follows:
1. **Downstream speed calculation:**
\[
\text{Downstream speed} = \frac{\text{Distance downstream}}{\text{Downstream time}}
\]
\[
\text{Downstream speed} = \frac{12 \text{ miles}}{2 \text{ hours}} = 6 \text{ mph}
\]
2. **Upstream speed calculation:**
\[
\text{Upstream speed} = \frac{\text{Distance upstream}}{\text{Upstream time}}
\]
\[
\text{Upstream speed} = \frac{12 \text{ miles}}{6 \text{ hours}} = 2 \text{ mph}
\]
3. **Boat speed and stream speed:**
- Let \( V_b \) be the speed of the boat in still water.
- Let \( V_s \) be the speed of the stream.
For downstream, \( V_b + V_s = 6 \text{ mph} \)
For upstream, \( V_b - V_s = 2 \text{ mph} \)
Solving these two equations, we get:
\[
V_b + V_s = 6
\]
\[
V_b - V_s = 2
\]
Adding the two equations:
\[
2V_b = 8 \implies V_b = 4 \text{ mph}
\]
Substituting \( V_b = 4 \text{ mph} \) into \( V_b + V_s = 6 \):
\[
4 + V_s = 6 \implies V_s = 2 \text{ mph}
\]
**Conclusion:**
- The speed of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F227fd297-25c6-41a3-8d4d-df25e1639e4d%2F6a0ec257-5e08-429b-a1c6-dda9893565b4%2F7ibhuts_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem Statement
A cruise boat travels 12 miles downstream in 2 hours and returns to its starting point upstream in 6 hours. Find the speed of the stream.
### Options
- **A.** 4.002 mph
- **B.** 6 mph
- **C.** 1.998 mph
- **D.** 10.002 mph
### Explanation
Given:
- Downstream distance: 12 miles
- Downstream time: 2 hours
- Upstream time: 6 hours
We can calculate the speeds as follows:
1. **Downstream speed calculation:**
\[
\text{Downstream speed} = \frac{\text{Distance downstream}}{\text{Downstream time}}
\]
\[
\text{Downstream speed} = \frac{12 \text{ miles}}{2 \text{ hours}} = 6 \text{ mph}
\]
2. **Upstream speed calculation:**
\[
\text{Upstream speed} = \frac{\text{Distance upstream}}{\text{Upstream time}}
\]
\[
\text{Upstream speed} = \frac{12 \text{ miles}}{6 \text{ hours}} = 2 \text{ mph}
\]
3. **Boat speed and stream speed:**
- Let \( V_b \) be the speed of the boat in still water.
- Let \( V_s \) be the speed of the stream.
For downstream, \( V_b + V_s = 6 \text{ mph} \)
For upstream, \( V_b - V_s = 2 \text{ mph} \)
Solving these two equations, we get:
\[
V_b + V_s = 6
\]
\[
V_b - V_s = 2
\]
Adding the two equations:
\[
2V_b = 8 \implies V_b = 4 \text{ mph}
\]
Substituting \( V_b = 4 \text{ mph} \) into \( V_b + V_s = 6 \):
\[
4 + V_s = 6 \implies V_s = 2 \text{ mph}
\]
**Conclusion:**
- The speed of
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