A cross staff of 1 cm notch is used to find the diameter of a celestial object at a distance of 36 x 108 m away from earth. Find the diameter
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A: Given data The diameter of the atom is d = 10-8 cm. The unit relation is given as 1 km = 1000 m and…
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A: 1 rad = 57.3 degree. So for 1 rad we required 57.3 degree. So 1 degree = (1/57.3) < 1 rad
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A: given Distance=1.542×109km
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A: gz=GMSzx2+z232 ∂g =GΔmd2 d=11 m =1100 cm Δm= V Δρ= 43πr3Δρ Δm = 52.35 x106 g/cm3
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A: Answer d) Astronomical unit
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A: GivenAngular diameter of body (θ)=0.35 °Distance between body=160 million km=160×106 km
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