A credit bureau analysis of undergradute students' credit records found that the average number of credit cards in an undergraduate's wallet was 4.9 ("Undergradute Students and Credit Cards in 2004," Nellie Mae, May 2005). It was also reported that in a random sample of 121 undergradute, the sample mean number of credit cards that the students said they carried was 2.6. The sample standard deviation was not reported, but for purpose of this exercise, suppose that is was 1.2. Test a hypothesis to check whether there is convincing evidence for the mean number of credit cards that undergradutes report carrying is less than the credit card bureau's figure of 4.09, with a significance level α = 0.01

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A: Let X be the students thant spend the average length of time (per week) on homework. Also,…

Q: Joan’s finishing time for the Bolder Boulder 10K race was 1.76 standard deviations faster than the…

A: Given   x=μ+1.76 σ   ∴z=1.76 ∵1.76 SD  above mean       n=420 women

Q: A National Center for Health Statistics study states that the mean height for adult men in the…

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Q: a 2003 study, the Accreditation Council for Graduate Medical Education found that medical residents’…

A: The formula of standardized z score for normal distribution is given by

Q: An online statistics professor recommends that students plan to spend approximately 15 hours per…

A: Given data,Mean (µ) = 15 hours Standard deviation (σ) =2.6 hours

Q: university in England and each student in a random sample of 38 female students from the same…

A: The following information has been provided: For Males : Sample Mean 1 (Xˉ1)(\bar X_1)= 282282…

Q: The test statistic is The p-value is Should the null hypothesis be rejected?

A: here from given information  for gamer in age- group 16-25 x1¯ = 42.5 σ1 = 9.5 n1 = 351    for gamer…

Q: company has surveyed 40 customers who shop on a particular online commerce platform and the company…

A: Given that  Mean = 23 , Standard deviation = 14

Q: According to a new study by ABC, the average time spent by young adults ages 20 to 25 in using their…

A: Given information Level of significance=0.10, n=sample size=30, sample mean x̄=7.8, s=sample…

Q: According to the Bureau of Labor Statistics, the mean salary for registered nurses in Kentucky was…

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Q: (120 minutes). What would you need to know to determine if the one-sample t test is an appropriate…

A: a. Explain whether it is acceptable to assume that the distribution of time spent playing video or…

Q: According to data from the 2010 United States Census, 64.2% of Americans in Susanville, CA were…

A: 64.2% of Americans in Susanville, CA were male, p = 0.642 Sample size, n = 100 Among the sample, 54…

Q: Suppose that another sample of resting heart rates for five Math students was obtained: 72, 68, 66,…

A: From the given data we want to know the data value .

Q: for a particular diamond mine ,80% of all the diamonds fail to qualify as gemstones grade. a random…

A: Given data, n=113 p=80%=0.80 q=1-p=0.20 Standard deviation=?

Q: Students at a major university are complaining of a serious housing crunch. They complain that many…

A: mean=14.3, standard deviations=3.9

Q: Suppose that for a certain individual credit card purchases follow a normal distribution with mean…

A: The normal distribution has a property called “68-95-99 rule” that 68% of the values lie in the…

Q: fitness center is interested in finding a 95% CI for the mean number of days per week that Americans…

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Q: A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches.…

A: Given that: X is normal Distributed with mean µ = 64.7 and standard deviation σ = 2.88 By using…

Q: An economist would like to estimate the mean amount of money that a family spends to within $45. If…

A:

Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…

A: The sample size is 130, sample mean is 58, and sample standard deviation is 53.

Q: A survey found that​ women's heights are normally distributed with mean 63.863.8 in and standard…

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Q: A college placement office conducted a survey of 100 engineers who had graduated from Stanford…

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Q: A laptop producer has been getting complaints on the batteries they install. Particularly, the…

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Q: York Manufacturing Inc. offers dental insurance to its employees. A recent study by the human…

A: Population mean μ =1234 Population standard deviation =321

Q: A hospital president claims that the average Salary of registered nurses at her hospital is more…

A:

Q: Is this unusual?.

A: From checking Facebook while walking to class to posting photos on Instagram while eating in the…

Q: The America Automobile Association reported that the mean price of a gallon of regular grade…

A: Hypothesis  Ho: mu=2.82,H1: mu<2.82  n=50, Xbar=2.77, s=0.15 Alpha=0.05=level of significance…

Q: Steve believes that his wife's cell phone battery does not last as long as his cell phone battery.…

A: The pooled variance is 28.2841.The degrees of freedom is,

Q: Joan’s finishing time for the Bolder Boulder 10K race was 1.67 standard deviations faster than the…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: A credit bureau analysis of undergraduate students' credit records found that the average number of…

A: State the hypotheses. That is, there is no evidence to conclude that the mean number of credit…

Q: ureau reports that 82% of Americans over the age of 25 are high school graduates. A survey of…

A: a. Given: n=1250,p=0.82 The mean is computed as: The variance is computed as: The standard…

Q: A researcher collected data from Boston police officers and found that on average they spent 14.3…

A:

Q: A credit bureau analysis of undergraduate students' credit records found that the average number of…

A:

Q: Suppose that water usages in American showers are normally distributed, with an average shower using…

A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

Q: a small company is looking to see if they have reached their goal of $30.20, in saving per family.…

A:

Q: A company conducted a survey on the number of hours employees spend on a particular task per week.…

A: Solution:To calculate the standard deviation, follow these steps:Step 1: Find the mean (average) of…

Q: , The following salaries (in pesos) were obtained from a sample of 12 executive secretaries: 7,500…

A: Given: n = 12 Data : 7500, 8400, 13000, 5800, 10300, 6300, 10600, 9200, 7600, 7500, 8350, 9466

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.