) A course repeater claims that his brother who did some Calculus at college years ago, bu urrently on some cough medication, believes that the first derivative of is f'(x) = 2-1+집+3-전+1 [(2x² – 1)(x² + 3) (2x2 – 1)(x² + 3) x) = 4x 2х 2x x2 +1 x2 +1 nd (x² + 8)7 (2 – 3x2)5 sing the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 30x is g'(x) = 14x %3D at the first derivative of g(x): x² + 8 *2– 3x 2 – %3D - - onfirm whether his brother is right, wrong or a little tipsy.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
For question 1 can you explain how the right hand side f'(x) can be expanded or integrated to get back the left hand side f(x)? Basically, the question in reverse.
ined in Unit 1 and 2, verify whether the limit to infinity of n(n+ 1)(n+ 2)-(n+ 3)-1
is equal to one.
A
and that h(T) = T2-2T-7,find h(7).
(4) Given matrix A =
3
Problem Set D
1) A course repeater claims that his brother who did some Calculus at college years ago, but
currently on some cough medication, believes that the first derivative of
(2x2 – 1)(x² + 3)
(x) =
[(2x² – 1)(x² +3)]
x2 +1
4x
2x
2x
-is f'(x) =
x2 +1
I2x² – 1 * x² + 3¯ x² + 1
and
30x
(x² + 8)7
(x² + 8)7
(2– 3x2)5
Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you
14x
hat the first derivative of g(x) =
is g'(x) = 2+8 2-3x²] [(2 – 3x²)³]
%3D
-
confirm whether his brother is right, wrong or a little tipsy.
Transcribed Image Text:ined in Unit 1 and 2, verify whether the limit to infinity of n(n+ 1)(n+ 2)-(n+ 3)-1 is equal to one. A and that h(T) = T2-2T-7,find h(7). (4) Given matrix A = 3 Problem Set D 1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of (2x2 – 1)(x² + 3) (x) = [(2x² – 1)(x² +3)] x2 +1 4x 2x 2x -is f'(x) = x2 +1 I2x² – 1 * x² + 3¯ x² + 1 and 30x (x² + 8)7 (x² + 8)7 (2– 3x2)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you 14x hat the first derivative of g(x) = is g'(x) = 2+8 2-3x²] [(2 – 3x²)³] %3D - confirm whether his brother is right, wrong or a little tipsy.
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