A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equ to that of Jupiter's orbit around the Sun (7.78 x 1011 m). What is the magnetic field (in T) in that region of space? 8.90e^-13 X Your answer cannot be understood or graded. More Information T

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### Cosmic-Ray Proton Motion in Magnetic Fields

**Scenario 1:**  
A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equal to that of Jupiter's orbit around the Sun (7.78 × 10¹¹ m). What is the magnetic field (in T) in that region of space?

- Incorrect Answer: **8.90e^-13**  
- Feedback: *Your answer cannot be understood or graded.*

**Scenario 2: What If?**  
The cosmic ray proton enters our solar system where the interplanetary magnetic field has a magnitude of 5.00 nT and is perpendicular to the velocity of the proton. What is the radius (in m) of the proton's circular orbit in this field?

- Correct Answer: **1.38e8 m**

Note: The second scenario calculates the radius of the proton's orbit when it encounters a magnetic field in our solar system.
Transcribed Image Text:### Cosmic-Ray Proton Motion in Magnetic Fields **Scenario 1:** A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equal to that of Jupiter's orbit around the Sun (7.78 × 10¹¹ m). What is the magnetic field (in T) in that region of space? - Incorrect Answer: **8.90e^-13** - Feedback: *Your answer cannot be understood or graded.* **Scenario 2: What If?** The cosmic ray proton enters our solar system where the interplanetary magnetic field has a magnitude of 5.00 nT and is perpendicular to the velocity of the proton. What is the radius (in m) of the proton's circular orbit in this field? - Correct Answer: **1.38e8 m** Note: The second scenario calculates the radius of the proton's orbit when it encounters a magnetic field in our solar system.
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