### Cosmic-Ray Proton Motion in Magnetic Fields**Scenario 1:** A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equal to that of Jupiter's orbit around the Sun (7.78 × 10¹¹ m). What is the magnetic field (in T) in that region of space?- Incorrect Answer: **8.90e^-13** - Feedback: *Your answer cannot be understood or graded.***Scenario 2: What If?** The cosmic ray proton enters our solar system where the interplanetary magnetic field has a magnitude of 5.00 nT and is perpendicular to the velocity of the proton. What is the radius (in m) of the proton's circular orbit in this field?- Correct Answer: **1.38e8 m**Note: The second scenario calculates the radius of the proton's orbit when it encounters a magnetic field in our solar system.

Given that The energy of the proton (E) = 23.0Mev The radius is (R) = 7.78*1011 m If v is the velocity of the proton which is mathematically deduced from the formula for kinetic energy as E = 12mv2v = 2Em Where m is the mass of proton with value m = 1.6×10-27Kg so the velocity of the proton will be v = 2×23×106×1.6×10-191.6×10-27v = 6.64×107m/s Generally the magnetic field is mathematically represented as B =mvRqB = 1.67×10-27×6.64×1077.78×1011×1.6×10-19B = 8.91×10-13 T Dear student you can write answer like this 8.90*e-13 T on your answer column.

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A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equ to that of Jupiter's orbit around the Sun (7.78 x 1011 m). What is the magnetic field (in T) in that region of space? 8.90e^-13 X Your answer cannot be understood or graded. More Information T

A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equ to that of Jupiter's orbit around the Sun (7.78 x 1011 m). What is the magnetic field (in T) in that region of space? 8.90e^-13 X Your answer cannot be understood or graded. More Information T

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

### Cosmic-Ray Proton Motion in Magnetic Fields

**Scenario 1:**
A cosmic-ray proton in interstellar space has an energy of 23.0 MeV and executes a circular orbit having a radius equal to that of Jupiter's orbit around the Sun (7.78 × 10¹¹ m). What is the magnetic field (in T) in that region of space?

- Incorrect Answer: **8.90e^-13**
- Feedback: *Your answer cannot be understood or graded.*

**Scenario 2: What If?**
The cosmic ray proton enters our solar system where the interplanetary magnetic field has a magnitude of 5.00 nT and is perpendicular to the velocity of the proton. What is the radius (in m) of the proton's circular orbit in this field?

- Correct Answer: **1.38e8 m**

Note: The second scenario calculates the radius of the proton's orbit when it encounters a magnetic field in our solar system.

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