A copper wire of length 25.0 cm is in a magnetic field of 0.36 T. If it has a mass of 11.0 g, what is the minimum current through the wire that would cause a magnetic force equal to its weight? 12 A 0.48 A 1.2 A 0.75 A 3.3 A

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### Magnetic Force on a Current-Carrying Wire

A copper wire of length 25.0 cm is placed in a magnetic field of 0.36 T (tesla). If it has a mass of 11.0 g, what is the minimum current through the wire that would result in a magnetic force equal to its weight?

- Options:
  - 12 A 
  - 0.48 A 
  - 1.2 A 
  - 0.75 A 
  - 3.3 A 

This question involves the interaction between electricity and magnetism, specifically how a current-carrying wire experiences a force when placed in a magnetic field. The force can be calculated using the formula:

\[ F = BIL \]

Where:
- \( F \) is the magnetic force,
- \( B \) is the magnetic field strength,
- \( I \) is the current in the wire,
- \( L \) is the length of the wire.

For the wire's weight \( W \) to equal the magnetic force \( F \), we equate \( F \) to \( W = mg \) (where \( m \) is the mass and \( g \) is the acceleration due to gravity).

### Explanation of Options

- Calculate the force necessary to counteract the wire's weight using its given mass.
- Use the relationship \( F = BIL \) to solve for \( I \), and identify which of the provided options matches the calculated current.
Transcribed Image Text:### Magnetic Force on a Current-Carrying Wire A copper wire of length 25.0 cm is placed in a magnetic field of 0.36 T (tesla). If it has a mass of 11.0 g, what is the minimum current through the wire that would result in a magnetic force equal to its weight? - Options: - 12 A - 0.48 A - 1.2 A - 0.75 A - 3.3 A This question involves the interaction between electricity and magnetism, specifically how a current-carrying wire experiences a force when placed in a magnetic field. The force can be calculated using the formula: \[ F = BIL \] Where: - \( F \) is the magnetic force, - \( B \) is the magnetic field strength, - \( I \) is the current in the wire, - \( L \) is the length of the wire. For the wire's weight \( W \) to equal the magnetic force \( F \), we equate \( F \) to \( W = mg \) (where \( m \) is the mass and \( g \) is the acceleration due to gravity). ### Explanation of Options - Calculate the force necessary to counteract the wire's weight using its given mass. - Use the relationship \( F = BIL \) to solve for \( I \), and identify which of the provided options matches the calculated current.
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