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A copper penny dropped into a solution of nitric acid produces a mixture of nitrogen oxides. The following reaction describes the formation of NO, one of the products. 3Cu(s)+8H*(aq) +2NO, (aq) → 2NO(g) + 3Cu²*(aq) + + 4H,0(1) Using the provided standard potentials, calculate E°cell for this reaction. 4H*(aq) +NO,(aq) + 3e¯ → NO(g) + 2H,0(1) E° = 0.96 V Cu²+ (aq) +2e¯ → Cu(s) E° = 0.3419 V 1st attempt

A copper penny dropped into a solution of nitric acid produces a mixture of nitrogen oxides. The following reaction describes the formation of NO, one of the products. 3Cu(s)+8H*(aq) +2NO, (aq) → 2NO(g) + 3Cu²*(aq) + + 4H,0(1) Using the provided standard potentials, calculate E°cell for this reaction. 4H*(aq) +NO,(aq) + 3e¯ → NO(g) + 2H,0(1) E° = 0.96 V Cu²+ (aq) +2e¯ → Cu(s) E° = 0.3419 V 1st attempt

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A copper penny dropped into a solution of nitric acid produces a mixture of nitrogen oxides. The following reaction describes the formation of NO, one of the products. 3Cu(s)+8H*(aq) + 2NO,(aq) → 2NO(g) +3Cu²+(aq) + 4H,0(1) Using the provided standard potentials, calculate E°cell for this reaction. 4H*(aq) + NO,(aq) +3e¯ → NO(g) + 2H,0(1) E° = 0.96 V Cu2+ (aq) +2e¯ → Cu(s) E° = 0.3419 V 1st attempt See Periodic Table O See Hint V
Transcribed Image Text:A copper penny dropped into a solution of nitric acid produces a mixture of nitrogen oxides. The following reaction describes the formation of NO, one of the products. 3Cu(s)+8H*(aq) + 2NO,(aq) → 2NO(g) +3Cu²+(aq) + 4H,0(1) Using the provided standard potentials, calculate E°cell for this reaction. 4H*(aq) + NO,(aq) +3e¯ → NO(g) + 2H,0(1) E° = 0.96 V Cu2+ (aq) +2e¯ → Cu(s) E° = 0.3419 V 1st attempt See Periodic Table O See Hint V
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