A convex spherical mirror has a radius of curvature of magnitude 38.0 cm. (a) Determine the position of the virtual image and the magnification for object distances of 27.0 cm. Indicate the location of the image with the sign of your answer. image location = cm magnification (b) Determine the position of the virtual image and the magnification for object distances of 47.0 cm. Indicate the location of the image with the sign of your answer. image location = cm magnification =
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- An object is placed a distance do = 17.0 cm in front of a concave (positive) mirror with a focal length f = 8.0 cm. What is the image distance for the image formed by this mirror? d₁ = What is the magnification for this image? m= cm Is the image upright or inverted? inverted upright no image is formed Is the image real or virtual? no image is formed virtual real h O C d. mirrorAn object (height = 7.7 cm) and its image are on opposite sides of a converging lens. The object is located 14.0 cm from the lens. The image is located 5.6 cm from the lens. Determine the image height (in cm). Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the image height is significant.A convex mirror has a focal length of -26 cm. Find the magnification produced by the mirror when the object distance is (a)11 cm and (b)21 cm. (a) m₁ = i (b) m₂ = i Object 2K Virtual image
- A concave mirror has a radius of curvature of 33.6 cm. Part A What is its focal length? 195] ΑΣΦΑ Submit Part B Request Answer ? cm A ladybug 7.30 mm tall is located 22.8 cm from this mirror along the principal axis. Find the location of the image of the insect.An object with a height of 39 cm is placed 1.6 m in front of a convex mirror with a focal length of -0.75 m. Part A Determine the approximate location of the image using a ray diagram. Express your answer using two significant figures. ? di = m behind the mirror Submit Request Answer Part B Determine the approximate size of the image using a ray diagram. Express your answer using two significant figures. ΑΣφ ? h; = cm Submit Request Answer Part C Is the image upright or inverted? upright inverted Submit Request Answer O OHand Written please.
- The same object is placed at different distances d in front of six different concave spherical mirrors. Each mirror has the focal length flisted below. ▾ Part A Which, if any, of these scenarios produce a real image? Which, if any, of these scenarios produce a virtual image? Sort the following scenarios into the appropriate bins. ▸ View Available Hint(s) real image Submit Part B inverted image Submit Request Answer Part C largest d=20 cm |f=10 cm Submit Which, if any, of these scenarios produce an inverted image? Which, if any, of these scenarios produce an upright image? Sort the following scenarios into the appropriate bins. Provide Feedback d = 15 cm f = 5 cm d = 15 cm f = 5 cm d = 15 cm f = 20 cm| d = 15 cm f = 20 cm| d = 20 cm f = 10 cm d = 10 cm |f=5 cm d=5 cm f = 20 cm Rank the images on the basis of the magnitude of their magnification. Rank these from largest to smallest. To rank items as equivalent, overlap them. ▸ View Available Hint(s) virtual image d=10 cm d = 10 cm f = 20…All problems involve a concave (converging) mirror that has a radius of curvature of 18.0 m.For problems 1-4, an object of height 12.0 cm is placed 15.00 m in front of the mirror. Calculate the image distance, the image height, and the magnification(not necessarily in that order). 1) Calculate di. 2) Calculate hi. 3) Calculate the magnification m. 4) Where is the image formed? A) on the object side of the optic B) on the side of the optic opposite the object C) there is no image formedAn object 1.40 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high. What is the magnification? magnification: Where is the image? image distance: cm Find the magnitude of the radius of curvature of the convex mirror formed by the cornea. magnitude of radius of curvature: cm Note: This technique is used by optometrists to measure the curvature of the cornea for contact lens fitting. The instrument used is called a keratometer, or curve measurer.
- An object is 12.0 cm from a converging lens (focal length = 15.0 cm). Determine the image magnification. Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the magnification is significant.The magnitude of the focal length of a concave lens is 20.00 cm. An object isplaced at 30.00 cm from the lens.a. Do the ray tracing of an object of length 5.0 cm perpendicular to the axis.b. Is the image real or virtual? c. Is the image upright or inverted? d. Where will the image form? e. What is the magnification?Photographs at a scale of S are required to cover an area X-mi square. The camera has a focal length f and focal plane dimensions of 9 × 9 in. If endlap is 60% and sidelap 30%, how many photos will be required to cover the area for the data given below? Part A: Express your answer as an integer. S=1:6800; X=10; f=152.4mm