A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -56 cm are 176 cm apart. A 3.3-cm-tall object is 60 cm in front of the converging lens. | - • Part A You may want to review (Pages 996 - 997) Calculate the distance between image and diverging lens. For help with math skills, you may want to review: Express your answer to two significant figures and include the appropriate units. Rearrangement of Expressions Involving Multiplication and Division • View Available Hint(s) Rearrangement of Algebraic Expressions Hint 1. How to approach the problem Draw a sketch showing the object and the two lenses. Label the distance from the object to the converging lens and the separation between the diverging and converging lenses. The light is going to go through both lenses. How is the image from the first lens related to what would be the object of the second lens? Applying the thin lens equation, what is the image distance for the first (converging) lens? What is the significance of the sign of the image distance? Mark this position on your sketch. What is the distance of this image from the second diverging lens? What is the object distance for the second lens? Applying the thin lens equation, what is the image distance for the second (diverging) lens? Again, what is the significance of the sign of the image distance? What is the distance of this final image from the diverging lens? HẢ Value Units Submit Request Answer |- • Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. v View Available Hint(s) Hint 1. How to approach the problem For a single lens, how are the height of the image and the height of the object related to magnification? What is the meaning of a negative magnification? How is the magnification determined by the image and object distances? For two lenses, how is the net magnification related to the magnification of each lens? Using the object and image distances from Part A, what is the net magnification? Given the height of the object, what is the height of the final image? What is the significance of the sign of the image height? HA Value Units

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A converging lens with a focal length of 40 cm and a diverging lens
with a focal length of -56 cm are 176 cm apart. A 3.3-cm-tall object
is 60 cm in front of the converging lens.
| -
• Part A
You may want to review (Pages 996 - 997)
Calculate the distance between image and diverging lens.
For help with math skills, you may want to review:
Express your answer to two significant figures and include the appropriate units.
Rearrangement of Expressions Involving Multiplication and Division
• View Available Hint(s)
Rearrangement of Algebraic Expressions
Hint 1. How to approach the problem
Draw a sketch showing the object and the two lenses. Label the distance from the object to the converging lens and the separation between the diverging and converging lenses.
The light is going to go through both lenses. How is the image from the first lens related to what would be the object of the second lens?
Applying the thin lens equation, what is the image distance for the first (converging) lens? What is the significance of the sign of the image distance? Mark this position on your sketch.
What is the distance of this image from the second diverging lens? What is the object distance for the second lens?
Applying the thin lens equation, what is the image distance for the second (diverging) lens? Again, what is the significance of the sign of the image distance? What is the distance of this final image from the diverging lens?
HẢ
Value
Units
Submit
Request Answer
|-
• Part B
Calculate the image height.
Express your answer to two significant figures and include the appropriate units.
v View Available Hint(s)
Hint 1. How to approach the problem
For a single lens, how are the height of the image and the height of the object related to magnification? What is the meaning of a negative magnification?
How is the magnification determined by the image and object distances? For two lenses, how is the net magnification related to the magnification of each lens?
Using the object and image distances from Part A, what is the net magnification? Given the height of the object, what is the height of the final image? What is the significance of the sign of the image height?
HA
Value
Units
Transcribed Image Text:A converging lens with a focal length of 40 cm and a diverging lens with a focal length of -56 cm are 176 cm apart. A 3.3-cm-tall object is 60 cm in front of the converging lens. | - • Part A You may want to review (Pages 996 - 997) Calculate the distance between image and diverging lens. For help with math skills, you may want to review: Express your answer to two significant figures and include the appropriate units. Rearrangement of Expressions Involving Multiplication and Division • View Available Hint(s) Rearrangement of Algebraic Expressions Hint 1. How to approach the problem Draw a sketch showing the object and the two lenses. Label the distance from the object to the converging lens and the separation between the diverging and converging lenses. The light is going to go through both lenses. How is the image from the first lens related to what would be the object of the second lens? Applying the thin lens equation, what is the image distance for the first (converging) lens? What is the significance of the sign of the image distance? Mark this position on your sketch. What is the distance of this image from the second diverging lens? What is the object distance for the second lens? Applying the thin lens equation, what is the image distance for the second (diverging) lens? Again, what is the significance of the sign of the image distance? What is the distance of this final image from the diverging lens? HẢ Value Units Submit Request Answer |- • Part B Calculate the image height. Express your answer to two significant figures and include the appropriate units. v View Available Hint(s) Hint 1. How to approach the problem For a single lens, how are the height of the image and the height of the object related to magnification? What is the meaning of a negative magnification? How is the magnification determined by the image and object distances? For two lenses, how is the net magnification related to the magnification of each lens? Using the object and image distances from Part A, what is the net magnification? Given the height of the object, what is the height of the final image? What is the significance of the sign of the image height? HA Value Units
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