A converging lens with a 25-cm focal length is placed50cm in front of a diverging lens having a focal length of -40 cm. An object 2 cm tall is placed 30 cm in front of the converging lens. Determine (a) the location of the final image, (b) its orientation, and (c) whether it is real or virtual.
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- A converging lens with a 25-cm focal length is placed50cm in front of a diverging lens having a focal length of -40 cm. An object 2 cm tall is placed 30 cm in front of the converging lens. Determine (a) the location of the final image, (b) its orientation, and (c) whether it is real or virtual.
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- A diverging lens (f=-12.0 cm) is located 22.0 cm to the left of a converging lens (f=34.0 cm). A 3.70 cm tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image (including the proper algebraic sign)?In a two-lens system, the focl length of the lens is f1 = 4.00 cm, and that of then lens 2 is f2 = 8.00 cm. The distance between the lenses is 16 cm. If an object O is 2.00 cm high and is placed 6.00 cm in front of the lens 1, where is the final image through the two-lens system?A converging lens (f = 12.3 cm) is located 44.9 cm to the left of a diverging lens (f = -7.16 cm). A postage stamp is placed 38.3 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification. (a) Number i (b) Number Units Units
- The focal length of a diverging lens is negative. If f = −16 cm for a particular diverging lens, where will the image be formed of an object located 45 cm to the left of the lens on the optical axis? cm to the left of the lensWhat is the magnification of the image?An object is initially at rest, 100 cm from a converging lens with a focal length of 30.0 cm. The object accelerates toward the lens at a constant rate of 0.300 cm/s?. At what time will the magnification of the image produced be -2.00?not a graded assignment
- An object is placed 25 cm in front of a converging lens of focal length 20 cm. 30 cm past the first lens is a second diverging lens of magnitude focal length 25 cm. What are the resulting image position relative to second lens and total magnification of the object in this setup?A converging lens of focal length 20 cm is placed 30 cm in front of another converging lens of focal length 4.0 cm. An object is placed 100 cm in front of the first lens. Determine(a) the location of the final image, (b) its orientation, and (c)whether it is real or virtual.An object of 1 cm tall is placed 3cm in front of a converging lens of focal length of 2 cm. (a) Use ray tracing to find the image. (b) Use the lens equation to find the image distance and compare it to your ray tracing and find the percentage error.
- An object is 21 cm in front of a diverging lens that has a focal length of -9.6 cm. How far in front of the lens should the object be placed so that the size of its image is reduced by a factor of 2.6?Suppose an object such as a book page is held 7.50 cm from a concave lens of focal length –10.0 cm. Such a lens could be used in eyeglasses to correct pronounced nearsightedness. (a) Using the thin lens equations to calculate the location of the image. (b) What magnification is produced? (c) Use ray tracing to get an approximate location for the image.A 1.00-cm-high object is placed 4.35 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position |-7.8 X cm in front of the second lens v height cm