A continuous-time signal is sampled 44,100 times per second, resulting in a sequence of values defined recursively as Yn+2-y₁ =3", n=0,1,2,... where y₁ = 0 and y₁ = 1. An application of Z-transform on the sequence resulted in the equation Y(=)_ Z z-2 (2-3)(²-1) By using inverse Z-transform on the above equation, produce the explicit form of y₁.
A continuous-time signal is sampled 44,100 times per second, resulting in a sequence of values defined recursively as Yn+2-y₁ =3", n=0,1,2,... where y₁ = 0 and y₁ = 1. An application of Z-transform on the sequence resulted in the equation Y(=)_ Z z-2 (2-3)(²-1) By using inverse Z-transform on the above equation, produce the explicit form of y₁.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A continuous-time signal is sampled 44,100 times per second, resulting in a sequence of
values defined recursively as Yn+2-y₁ =3", n=0,1,2,... where y₁ = 0 and y₁ = 1. An
application of Z-transform on the sequence resulted in the equation
Y(z) _.
z-2
Z
(z− 3)(z²−1)*
By using inverse Z-transform on the above equation, produce the explicit form of y₁.
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