A continuous random variable X has a pdf of the form: f(x) = (620/801) x^3, for 0.42< X<1.51. Calculate the standard deviation (sigma) of X. Your answer: O 0.277 O 0.679 O 0.320 O 0.444 O 0.999 O 0.731
A continuous random variable X has a pdf of the form: f(x) = (620/801) x^3, for 0.42< X<1.51. Calculate the standard deviation (sigma) of X. Your answer: O 0.277 O 0.679 O 0.320 O 0.444 O 0.999 O 0.731
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![A continuous random variable X has a pdf
of the form: f(x) = (620/801) x^3, for 0.42<
X<1.51. Calculate the standard deviation
(sigma) of X.
Your answer:
0.277
O 0.679
0.320
0.444
0.999
0.731
O 0.238
0.822
O 0.383
0.268](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F195492cc-33fa-412b-9d6b-00b1ec8fc02f%2Fa402f655-2a05-4245-b25b-60a1db839b20%2F7at5d2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A continuous random variable X has a pdf
of the form: f(x) = (620/801) x^3, for 0.42<
X<1.51. Calculate the standard deviation
(sigma) of X.
Your answer:
0.277
O 0.679
0.320
0.444
0.999
0.731
O 0.238
0.822
O 0.383
0.268
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