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A container of water has been outdoors in cold
weather until a 5.0-cm thick slab of ice has
formed on its surface. The air above the ice is
Data:
kice = 1.7 W/m-K
Pice = 0.92 g/cm³
Le,ice = 333 kJ/kg
%3D
at -10°C.
Assume that the walls of the container are
Calculate the rate of formation of ice (in
cm/hr) on the bottom surface of the slab.
thermally insulating.

Expert Solution

Step 1

Given

Thickness (y) = 5.0 cm = 0.05 m

Temperature $(θ)$ = $- 10 ° C$ ( Temperature difference $θ = 0 ° - (- 10 °)) = 10 ° C$

$k_{ice} = 1.7 W / m . K ρ_{ice} = 0.92 g / {cm}^{3} = 920 kg / m^{3} L_{f, ice} = 333 kJ / kg = 333 \times 1000 J / kg$

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