A consumer organization wants to estimate the actual tread wear index of a brand name of tires that claims "graded150"on the sidewall of the tire. A random sample ofn=19indicates a sample mean tread wear index of148.7and a sample standard deviation of22.3.Complete parts (a) through (c).a.Assuming that the population of tread wear indexes is normally distributed, construct a90%confidence interval estimate of the population mean tread wear index for tires produced by this manufacturer under this brand name. nothing≤μ≤nothing(Round to two decimal places as needed.)

The summary of the statistics is, x¯=148.7,s=22.3,n=19 The degree of freedom is, df=n-1 =19-1 =18 Critical values: By using the t-tables, the critical value at 10% level of significance with df = 18 for a two tailed t -distribution is, t0.10/2=±1.734The 90% confidence interval estimate of the population mean tread wear index for tires produced by this manufacturer under this brand name is, Therefore, the required confidence interval is,

Answered: A consumer organization wants to…

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter10: Statistics

Section10.5: Comparing Sets Of Data

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A consumer organization wants to estimate the actual tread wear index of a brand name of tires that claims "graded

150"

on the sidewall of the tire. A random sample of

n=19

indicates a sample mean tread wear index of

148.7

and a sample standard deviation of

22.3.

Complete parts (a) through (c).

a.	Assuming that the population of tread wear indexes is normally distributed, construct a 90% confidence interval estimate of the population mean tread wear index for tires produced by this manufacturer under this brand name.

nothing≤μ≤nothing

(Round to two decimal places as needed.)

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