A consumer group claims that the average annual consumption ofhigh fructose corn syrup by a person in the U.S. is 48.8 pounds.You believe it is higher. You take a simple random sample of 34people in the U.S. and find an average of 52.9 pounds with astandard deviation of 4.8 pounds. Test at 5% significance.Round to the fourthHo: Select an answerHA: Select an answerTest Statistic:Select an answerSelect an answerP-value:Did something significant happen? | Select an answerSelect the Decision Rule: Select an answerThere Select an answer enough evidence to concludeSelect an answerSubmit Question

From the provided information, Sample size (n) = 34 Sample mean (x̄) = 52.9 Sample standard…

Answered: A consumer group claims that the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Given a sample data set with a Standard Deviation of 1.34, what is the Variance of the data set.? Round your answer to two digits after the decimal point.
You are given n = 5 measurements 2, 1, 1, 3, 5. Find the sample standard deviation
Consider the following data: −9,13,−14,−14,−9,−14,−9−9,13,−14,−14,−9,−14,−9 Copy Data Step 2 of 3: Calculate the value of the sample standard deviation. Round your answer to one decimal place.
Six students took a chemistry quiz. Their scores are listed below. Calculate the experimental standard deviation. Quiz scores: 16, 13, 14, 9.0, 18, 21
Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.272.452.542.432.752.372.192.421.911.432.851.731.992.322.332.704.742.873.382.722.833.423.952.993.873.473.082.942.703.602.842.373.033.232.593.643.242.662.352.432.813.952.522.922.983.412.272.562.933.162.201.151.934.002.542.832.352.311.522.801.951.602.452.332.081.553.201.491.812.551.662.352.452.082.192.752.002.792.392.671.692.881.841.991.862.561.972.183.671.553.162.461.881.502.793.283.822.752.452.712.541.642.183.032.361.481.922.322.651.411.391.802.242.302.481.732.402.442.482.44
Calculate the following data: 1,14,12,10,15,8 Calculate the value of the sample standard deviation. Round your answer to one decimal place.
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In the 1992 presidential election, Alaska's 40 election districts averaged 2038 votes per district for President Clinton. The standard deviation was 576. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places.a. What is the distribution of X? X ~ N(,)b. Is 2038 a population mean or a sample mean? Select an answer Population Mean Sample Mean c. Find the probability that a randomly selected district had fewer than 1842 votes for President Clinton. d. Find the probability that a randomly selected district had between 1997 and 2099 votes for President Clinton. e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number.
Use the magnitudes (Richter scale) of the 120 earthquakes listed in the accompanying data table. Use technology to find the range, variance, and standard deviation. If another value, 8.00, is added to those listed in the data set, do the measures of variation change much? 3.30 2.77 2.80 1.96 1.69 2.54 2.43 3.44 3.92 1.58 2.87 1.63 2.56 3.95 2.50 2.44 1.82 2.19 2.44 2.99 2.92 2.35 1.98 3.06 2.78 3.86 2.95 2.07 1.86 2.36 2.37 3.46 3.45 1.54 2.54 1.49 2.22 3.06 2.27 3.20 1.96 1.91 2.40 2.95 2.61 1.49 2.16 2.33 1.91 2.70 2.92 1.80 3.66 2.69 1.43 3.60 3.13 2.56 1.54 1.41 2.83 2.85 2.20 1.68 3.18 1.38 1.73 2.37 1.15 2.35 2.46 1.81 2.01 3.00 1.94 2.42 1.85 2.24 2.35 3.22 3.97 2.10 1.48 2.31 2.31 2.62 2.55 2.20 2.77 2.46 2.69 3.57 2.84 2.75 3.26 1.74 4.72 3.23 2.36 2.00 3.83 2.41 2.88 2.67 2.32 2.80 2.80 2.40 3.41 2.34 1.49 2.41 2.45 2.50 2.73 2.44 2.78 2.65 2.68 2.43 Without the extra data value, the range is 3.573.57. (Type an integer or…
In the 1992 presidential election, Alaska's 40 election districts averaged 1989 votes per district for President Clinton. The standard deviation was 568. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. a. What is the distribution of X? X ~ N( __ , __ ) b. Is 1989 a population mean or a sample mean? Select an answer _______. c. Find the probability that a randomly selected district had fewer than 2087 votes for President Clinton. _____ d. Find the probability that a randomly selected district had between 1905 and 2194 votes for President Clinton.______ e. Find the first quartile for votes for President Clinton. Round your answer to the nearest whole number. ______
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Lily has been keeping track of what she spends on eating out. The last week’s expenditures for meals eaten out were $5.69, $5.95, $6.19, $10.91, $7.49, $14.53 and $7.66. The sample standard deviation is $10.58. TRUE OR FALSE

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