A consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16, and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical to that for type A. A random sample of n = 25 tubes of each type is selected, and Xpar B - Xpar a is computed. If µB equals or exceeds µA, the manufacturer would like to adopt type B for use. The observed difference is Xpar B - Xpar A = 3.5. What decision would you make and why?

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A consumer electronics company is comparing the brightness of two different types of picture tubes
for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16,
and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical
to that for type A. A random sample of n = 25 tubes of each type is selected, and Xpar 3 - Xpar a is
computed. If µB equals or exceeds µA, the manufacturer would like to adopt type B for use. The
observed difference is Xpar B - Xpar A = 3.5. What decision would you make and why?
Transcribed Image Text:A consumer electronics company is comparing the brightness of two different types of picture tubes for use in its television sets. Tube type A has mean brightness of 100 and standard deviation of 16, and tube type B has unknown mean brightness, but the standard deviation is assumed to be identical to that for type A. A random sample of n = 25 tubes of each type is selected, and Xpar 3 - Xpar a is computed. If µB equals or exceeds µA, the manufacturer would like to adopt type B for use. The observed difference is Xpar B - Xpar A = 3.5. What decision would you make and why?
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