A constructionengineer has been asked to recomment an excavator for acquisition. Threealternatives have been identified, having the characteristics shown in the following table.(MARR =12%)Useful lifeExcavatorAlternativeABс4 years5 years6 yearsInvestment$15,500$20,250$30,750Annual operationcost$8,750$5,850$3,175Terminal salvagevalue$2,500$3,000$3,250a) Apply present worth analysis.b) Use shortest life to establish the planning horizon's length and apply present wothanalysis again.c)Use longest life to establish the planning horizon's length and apply present woth analysisonce more.d) Repeat PW analysis for 10 years standard analysis period.e)Consider an infinitely long planning period and calculate the annual worth for eachinvestment alternatives.

Excavator PW Of Investment PW Of O&MPW Of Salvage…

Answered: A constructionengineer has been asked…

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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A portable concrete test instrument used in construction for evaluating and profiling concrete surfaces (MACRS-GDS 5-year property class) is under consideration by a construction firm for $25,500. The instrument will be used for 6 years and be worth $2,500 at that time. The annual cost of use and maintenance will be $13,000. Alternatively, a more automated instrument (same property class) available from the manufacturer costs $26,000, with use and maintenance costs of only $7,500 and salvage value after 6 years of $3,000. The marginal tax rate is 25%, and MARR is an after-tax 12%. Determine which alternative is less costly, based upon comparison of after-tax annual worth. Show the AW values used to make your decision.
If the MARR=10%, compute the value of X that makes the alternatives equally desirable. Do not use spreadsheets. Alternatives Machine A Machine B First cost $12,000 $20,000 Annual Operating cost $1,400/year X Salvage value $2,000 $3,000 Life 4 years 8 years
When lives are equal adjustments to cash flows are not required. The MEAS can be compared by directly comparing their equivalent worth (PW, FW, or AW) calculated using the MARR. The decision will be the same regardless of the equivalent worth method you use. For a MARR of 12%, select from among the MEAs below. Capital investment Annual revenues Annual expenses Market Value (EOL) Life (years) A -$150,000 $28,000 -$1,000 $20,000 10 Alternatives B -$85,000 $16,000 -$550 $10,000 10 C -$75,000 $15,000 -$500 $6,000 10 -$120,000 $22,000 -$700 $11,000 10
Compare the alternatives below on the basis of their capitalized costs. Assume the MARR is 10% per year, compounded annually Project A Project B Project C First cost ($200,000) ($275,000) ($800,000) Annual income $60,000 $70,000 $80,000 Salvage value $40,000 $60,000 $500,000 Life, years 4 7 infinity
Carlisle Company has been cited and must invest in equipment to reduce stack emissions or face EPA fines of $20,500 per year. An emission reduction filter will cost $75,000 and have an expected life of 5 years. Carlisle's MARR is 10%/year. Part a What is the future worth of this investment? $ Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is £10.
! Required information An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has an estimated first cost of $40,000, an annual operating cost (AOC) of $12,000, and a service life of 2 years. Method B will cost $70,000 to buy and will have an AOC of $6,000 over its 4-year service life. Method C costs $125,000 initially with an AOC of $3,500 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth 7% of its first cost. Perform a present worth analysis to select the method at /= 12% per year. The present worth of method A is $ The present worth of method B is $ The present worth of method C is $ ✓is selected. Method C
Company X is considering the purchase of a helicopter for connecting services between their base airport and the new inter-county airport being built about 30 miles away. It is believed that the chopper will be needed only for 6 years until the Rapid Transit Connection is phased in. The estimates on two types of helicopters under consideration, The Whirl 2 B and The ROT 8, are given below: The Whirl 2 B First Cost Annual Maintenance Salvage Value Useful life in years $95,000 $3,000 $12,000 The ROT 8 $120,000 $9,000 $25,000 6 3 Assuming that the Whirl 2B will be available in the future with identical costs, what is the annual cost advantage of selecting The Whirl 2B ? (Use an interest rate of 10 %) A. cost more than $4,000 C. cost between $4,000 and $3,000 B. save between $3,000 and $2000 D. save more than $4,000
A city government feels that the energy production capacity must be expanded to meet anticipated demands for energy. There are three alternatives to consider: @A nuclear facility with an investment of $250 million, operating costs of $3 million per year and life of 20 years. @ A coal plant with an investment of $200 million operating costs of $10 million per year and a life of 20 years. 26°C I P Type here to search
Problem 05.024 Alternative Comparison - Different Lives You and your partner have become very interested in cross-country motorcycle racing and wish to purchase entry-level equipment. You have identified two alternative sets of equipment and gear. Package K has a first cost of $250,000, an operating cost of $5,500 per quarter, and a salvage value of $30,000 after its 2-year life. Package L has a first cost of $170,000 with a lower operating cost of $3,500 per quarter and an estimated $25,000 salvage value after its 4-year life. Which package offers the lower present worth analysis at an interest rate of 8% per year, compounded quarterly? The present worth of package K is $[ and that of package L is $[ (Click to select) offers the lower present worth.
A portable concrete test instrument used in construction for evaluating and profiling concrete surfaces (MACRS-GDS 5-year property class) is under consideration by a construction firm for $24,000. The instrument will be used for 6 years and be worth $1,000 at that time. The annual cost of use and maintenance will be $11,000. Alternatively, a more automated instrument (same property class) available from the manufacturer costs $28,500, with use and maintenance costs of only $7,500 and salvage value after 6 years of $2,500. The marginal tax rate is 25%, and MARR is an after-tax 12%.Determine which alternative is less costly, based upon comparison of after-tax annual worth. select an alternative Show the AW values used to make your decision:Alternative 1: $enter a dollar amount Alternative 2:
Octavia Bakery is planning to purchase one of two ovens. The expected cash flows for each oven are shown below. MARR is 8%/year. Model 127B Model 334A Initial Investment $50,000 $80,000 Estimated Life 10 5 End of Life Salvage $10,000 $0 Annual Income $19,400 $26,000 Annual Expense $10,000 $6,000 2(a) What is the discounted payback period for each investment? 2(b) Which oven should Octavia Bakery purchase if they wish to minimize the DPBP? Answer:
Required information An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has an estimated first cost of $38,000, an annual operating cost (AOC) of $10,000, and a service life of 2 years. Method B will cost $79,000 to buy and will have an AOC of $3,000 over its 4-year service life. Method C costs $143,000 initially with an AOC of $3,000 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth 6% of its first cost. Perform a future worth analysis to select the method at i= 13% per year. The future worth of method A is $55118 The future worth of method B is $ The future worth of method C is $ Method B is selected.

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