(a) Construct a scatterplot of the data. 0.3 0.2 0.1 ELDE 0.0 -0.1 20 y O 0.3 0.2 0.1 -0.1 10 15 20 0.3 0.2. 0.1 0.0 -0.1 5 10 15 10 15 20 How would you describe the relationship between x and y? O There is an outlier in the lower left of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality. O There is an outlier in the upper right of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality. O There is an outlier in the upper left of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality. O There is an outlier in the lower right of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality. (c) What value of net directionality would you predict for a stream that had mean water temperature of 13°C? (Round your answer to four decimal places.) y 0.3 0.2 0.1 0.0 -0.1 (b) Find the equation of the least-squares line describing the relationship between y net directionality and x = mean water temperature. (Round your numerical values to four decimal places.) ŷ = 5 10 15 20 X Ⓡ

MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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The authors of a paper investigated whether water temperature was related to how far a salamander would swim and whether it would swim upstream or downstream. Data for 14 streams with different mean water temperatures where salamander larvae were released are given (approximated from a graph that appeared in the paper).
The two variables of interest are x = mean water temperature (°C) and y = net directionality, which was defined as the difference in the relative frequency of the released salamander larvae moving upstream and the relative frequency of released salamander larvae moving downstream. A positive value of net directionality means a higher proportion were moving
upstream than downstream. A negative value of net directionality means a higher proportion were moving downstream than upstream.
Mean Temperature (x)
6.22
8.01
8.67
10.51
12.4
12.04
12.55
17.93
18.34
19.84
20.3
19.12
17.68
19.57
USE SALT
Net Directionality (y)
-0.08
0.25
-0.14
0.00
0.08
0.03
-0.07
0.29
0.23
0.24
0.19
0.14
0.05
0.07
Transcribed Image Text:The authors of a paper investigated whether water temperature was related to how far a salamander would swim and whether it would swim upstream or downstream. Data for 14 streams with different mean water temperatures where salamander larvae were released are given (approximated from a graph that appeared in the paper). The two variables of interest are x = mean water temperature (°C) and y = net directionality, which was defined as the difference in the relative frequency of the released salamander larvae moving upstream and the relative frequency of released salamander larvae moving downstream. A positive value of net directionality means a higher proportion were moving upstream than downstream. A negative value of net directionality means a higher proportion were moving downstream than upstream. Mean Temperature (x) 6.22 8.01 8.67 10.51 12.4 12.04 12.55 17.93 18.34 19.84 20.3 19.12 17.68 19.57 USE SALT Net Directionality (y) -0.08 0.25 -0.14 0.00 0.08 0.03 -0.07 0.29 0.23 0.24 0.19 0.14 0.05 0.07
(a) Construct a scatterplot of the data.
y
0.3
0.2
0.1
0.0
-0.1
5
10
15
20
X
y
0.3
0.2
0.1
0.0
-0.1
5
10
15
20
X
y
0.3
0.2
0.1
0.0
-0.1
5
10
15
20
(c) What value of net directionality would you predict for a stream that had mean water temperature of 13°C? (Round your answer to four decimal places.)
X
How would you describe the relationship between x and y?
O There is an outlier in the lower left of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality.
O There is an outlier in the upper right of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality.
O There is an outlier in the upper left of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality.
O There is an outlier in the lower right of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality.
y
0.3
0.2
0.1
0.0
-0.1
(b) Find the equation of the least-squares line describing the relationship between y = net directionality and x = mean water temperature. (Round your numerical values to four decimal places.)
ŷ =
5
10
15
20
X
Transcribed Image Text:(a) Construct a scatterplot of the data. y 0.3 0.2 0.1 0.0 -0.1 5 10 15 20 X y 0.3 0.2 0.1 0.0 -0.1 5 10 15 20 X y 0.3 0.2 0.1 0.0 -0.1 5 10 15 20 (c) What value of net directionality would you predict for a stream that had mean water temperature of 13°C? (Round your answer to four decimal places.) X How would you describe the relationship between x and y? O There is an outlier in the lower left of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality. O There is an outlier in the upper right of the window. If we disregard that outlier, then there is a negative linear relationship between mean temperature and net directionality. O There is an outlier in the upper left of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality. O There is an outlier in the lower right of the window. If we disregard that outlier, then there is a positive linear relationship between mean temperature and net directionality. y 0.3 0.2 0.1 0.0 -0.1 (b) Find the equation of the least-squares line describing the relationship between y = net directionality and x = mean water temperature. (Round your numerical values to four decimal places.) ŷ = 5 10 15 20 X
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