A constant force of 50 lb is applied at an angle of 48° to pull a handcart 41 ft across the ground. What is the work done by this force (to 2 decimal places)? Work = 50 lb 48° 41 ft ft-lb
A constant force of 50 lb is applied at an angle of 48° to pull a handcart 41 ft across the ground. What is the work done by this force (to 2 decimal places)? Work = 50 lb 48° 41 ft ft-lb
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![# Applications
A constant force of 50 lb is applied at an angle of 48° to pull a handcart 41 ft across the ground. What is the work done by this force (to 2 decimal places)?
## Diagram Description:
- **Force Vector:** A diagonal arrow labeled "50 lb" represents the force applied at an angle.
- **Angle:** The angle between the force and the horizontal direction is 48°, marked near the origin of the vectors.
- **Distance Vector:** A horizontal line labeled "41 ft" represents the distance the cart is moved.
## Calculation:
To calculate the work done, use the formula:
\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]
Where:
- \( F = 50 \, \text{lb} \) (force)
- \( d = 41 \, \text{ft} \) (distance)
- \( \theta = 48^\circ \) (angle)
Enter the calculated work in the box labeled "Work = " followed by "ft-lb".](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F55a44e3d-6d6a-4ecd-9343-ab7bc7f808c7%2Fd2be1e56-8d85-4320-875a-04f89e45c924%2Fqtexb99_processed.png&w=3840&q=75)
Transcribed Image Text:# Applications
A constant force of 50 lb is applied at an angle of 48° to pull a handcart 41 ft across the ground. What is the work done by this force (to 2 decimal places)?
## Diagram Description:
- **Force Vector:** A diagonal arrow labeled "50 lb" represents the force applied at an angle.
- **Angle:** The angle between the force and the horizontal direction is 48°, marked near the origin of the vectors.
- **Distance Vector:** A horizontal line labeled "41 ft" represents the distance the cart is moved.
## Calculation:
To calculate the work done, use the formula:
\[ \text{Work} = F \cdot d \cdot \cos(\theta) \]
Where:
- \( F = 50 \, \text{lb} \) (force)
- \( d = 41 \, \text{ft} \) (distance)
- \( \theta = 48^\circ \) (angle)
Enter the calculated work in the box labeled "Work = " followed by "ft-lb".
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