A = Consider the matrix 0 0 6 181 -6-3010-60 15-200 and suppose that we have the following row reduction to its RREF B. 0 0 6 181 15-200 -6-3010-60 -6-3010-60 A= 15-200 006 181 15-200 15-200 00-2-60 001 30 00 6 181 006 181 150 6 0 001 30 15060 00130 = B 006181 00001 The row reduction gives us that B = E5E4E3E2E₁ A where 0 0 1 1 0 0 Ει = 0 1 0 |E₂ = E2 6 1 0 1 0 0 0 0 1 1 0 0 1 2 0 E3 = 0 -1/2 0 |E₁ = 0 1 O 0 0 0 1 0 0 1 1 0 0 E5 = 0 1 0 0 -6 1 We therefore have an invertible matrix U so that B = UA U =
A = Consider the matrix 0 0 6 181 -6-3010-60 15-200 and suppose that we have the following row reduction to its RREF B. 0 0 6 181 15-200 -6-3010-60 -6-3010-60 A= 15-200 006 181 15-200 15-200 00-2-60 001 30 00 6 181 006 181 150 6 0 001 30 15060 00130 = B 006181 00001 The row reduction gives us that B = E5E4E3E2E₁ A where 0 0 1 1 0 0 Ει = 0 1 0 |E₂ = E2 6 1 0 1 0 0 0 0 1 1 0 0 1 2 0 E3 = 0 -1/2 0 |E₁ = 0 1 O 0 0 0 1 0 0 1 1 0 0 E5 = 0 1 0 0 -6 1 We therefore have an invertible matrix U so that B = UA U =
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:A =
Consider the matrix
0 0 6 181
-6-3010-60
15-200
and suppose that we have the following row reduction to its RREF B.
0 0 6 181
15-200
-6-3010-60
-6-3010-60
A=
15-200
006 181
15-200
15-200
00-2-60
001 30
00 6 181
006 181
150 6 0
001 30
15060
00130
= B
006181
00001
The row reduction gives us that B = E5E4E3E2E₁ A where
0
0
1
1
0
0
Ει
=
0
1
0
|E₂ =
E2
6
1
0
1
0
0
0
0
1
1
0
0
1
2
0
E3 =
0
-1/2
0
|E₁ =
0
1
O
0
0
0
1
0
0
1
1
0
0
E5
=
0
1
0
0
-6
1
We therefore have an invertible matrix U so that B = UA
U =
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