(a) Consider the code segment below:int main(){int a - 5;int pid;printf (“a = %d\n", a);if (pid fork()) {for (int i=0;i <2; i++){fork();att;printf (“a = %d\n", a);else {for (int i=0;i <2; i++){a--;fork();printf ("a - %d\n", a);att;printf ("a = %d\n", a);return (0);You are required to:(i)Draw a process tree showing the processes created when the code above is executed.Label each process P1, P2, P3 and so on.(ii)Write down the output obtained from each process.

Answered: Image /qna-images/answer/69b3173f-2847-4e3f-9739-d13d33eaa9d6.jpg

Answered: (a) Consider the code segment below:…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Run the programme and identify the outputs: #include using namespace std; void Test (int , int,int []); void Test (int num, int numl, int z[]) { num=1001; numl=290; int main () { int x = 1; int y[3]; y[0]=1; Test (x,V[0],y); z[1]=34; z[2]=35; } cout<<"x is: cout<<"y[0] is: << x<< endl; <
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Make this C language code into modular code (functions) #include #include main() { char choice; int num1, num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root //choice-getch(); scanf("%c",&choice); if(choice=='s') { printf("\nEnter Value to calculate square root:"); scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:"); scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break; case '-': result = num1 - num2; printf("\nDifference is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '*': result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '/': result = num1 / num2; printf("\nQuotient is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1/num2);…
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* Find the result for the following program include doublevalue (int z) { z*=2; --z; return z;} int main( ) {int a, b; a=16; b=23; aa=doublevalue(a); bb=doublevalue(b); f=(aa%2) +bb+2; cout<
Make this C language code into modular code (functions) #include #include main() { char choice; int num1, num2, result = 0; while(1) { printf("\nEnter Operator(+,-, *, /,f, s):");//f for floor division and s for square root //choice-getch(); scanf("%c",&choice); if(choice=='s') { printf("\nEnter Value to calculate square root:"); scanf("%ld",&num1); } else{ printf("\nEnter First Value:"); scanf("%d",&num1); printf("\nEnter Second Value:"); scanf("%d",&num2); } switch (choice) { case '+': result = num1 + num2; printf("\nSum is = %d", result); break; case '-': result = num1 - num2; printf("\nDifference is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '*': result = num1 * num2; printf("\nProduct is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case '/': result = num1 / num2; printf("\nQuotient is = %d", result); printf("\n\nPress Enter Again for New Input\n"); break; case 'f'://floor division result = floor(num1/num2);…
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