A conservative force F(x) acts on a 2.0 kg particle that moves along the x axis. The potential energy U(x) associated with F(x) is graphed in the figure below. When the particle is at x = 2.5 m, its velocity is -2.0 m/s. The "kinks" in the graph occur at (1, -2.8), (4, -17.2), and (8.5, -17.2); and the endpoint is at (15,-2). 0 6-10 D-15 -20 0 ---Select-- 0 5 (a) What are the magnitude and direction of F(x) at this position? magnitude N direction x (m) 10 (c) What is its speed at x = 7.0 m? m/s (b) Between what limits of x does the particle move? m (smallest x-value) m (largest x-value) 15

A conservative force F(x) acts on a 2.0 kg particle that moves along the x axis. The potential energy U(x) associated with F(x) is graphed in the figure below. When the particle is at x = 2.5 m, its velocity is -2.0 m/s. The "kinks" in the graph occur at (1, -2.8), (4, -17.2), and (8.5, -17.2); and the endpoint is at (15,-2). 0 6-10 D-15 -20 0 ---Select-- 0 5 (a) What are the magnitude and direction of F(x) at this position? magnitude N direction x (m) 10 (c) What is its speed at x = 7.0 m? m/s (b) Between what limits of x does the particle move? m (smallest x-value) m (largest x-value) 15

Name: A conservative force F(x) acts on a 2.0 kg particle that moves along
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: A conservative force F(x) acts on a 2.0 kg particle that moves along the x axis. The potential energy U(x) associated withF(x) is graphed in the figure below. When the particle is at x = 2.5 m, its velocity is -2.0 m/s. The "kinks" in the graphoccur

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Q10
The figure here shows a plot of potential energy U versus position x of a 0.876 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.96 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.96 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? UcT UB 4 x (m) (a) Number i Unit (b) Number i Unit (c) (d) Number i…
Two blocks, of masses M = 2.1 kg and 2M, are connected to a spring of spring constant k = 370 N/m that has one end fixed, as shown in Figure. The horizontal surface and the pulley are frictionless, and the pulley has negligible mass. The blocks are released from rest with the spring relaxed. What is the kinetic energy of hanging block when it has fallen that 0.080 m? (Your result must be in Joules and include 2 digit after the decimal point. Maximum of 3% of error is accepted in your answer. Take g=9.8 m/s2.)
Protons and neutrons (together called nucleons) are held together in the nucleus of an atom by a force called the strong force. At very small separations, the strong force between two nucleons is larger than the repulsive electrical force between two protons--hence its name. But the strong force quickly weakens as the distance between the protons increases. A well-established model for the potential energy of two nucleons interacting via the strong force is U=U0[1−e−x/x0] where x is the distance between the centers of the two nucleons, x0 is a constant having the value x0 = 2.0 × 10−15 m, and U0 = 6.0 × 10−11 J. Quantum effects are essential for a proper understanding of nucleons, but let us innocently consider two neutrons as if they were small, hard, electrically neutral spheres of mass 1.67 ×10−27 kg and diameter 1.0 × 10−15 m. Suppose you hold two neutrons 9.0 × 10−15 m apart, measured between their centers, then release them.What is the speed of each neutron as they crash…
The figure here shows a plot of potential energy U versus position x of a 0.898 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, UB = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.52 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.52 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Uc UB UA 2 4 x (m) (a) Number i Unit (b) Number i Unit (c) (d)…
The figure below shows a plot of potential energy U versus position x of a 0.96 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are UA = 10.0 J, Ug = 25.0 J, and UC = 35.0 J. (r) Ucr UB 2 4 6 x (m) The particle is released at x = 4.5 m with an initial speed of 8.5 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.0 m, what is its speed there, and if it cannot, what is its turning point? ---Select-- C ---Select- (b) What are the magnitude and direction of the force on the particle as it begins to move to the left of x = 4.0 m? magnitude N direction Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.5 m at speed 8.5 m/s. (c) If the particle can reach x = 7.0 m, what is its speed there, and if it cannot, what is its turning point? Select C
Q.4. (a) Force F = (3×²N)i + (4N)j, with x in meters, acts on a particle, changing only the kinetic energy of the particle. How much work is done on the particle as it moves from coordinates (2 m, 3 m) to (3 m, 0 m)? (b) Does the speed of the particle increase, decrease, or remain the same?
A 0.5 kg ball experiences the one-dimensional, conservative force Fx as shown in Figure 1. The corresponding potential energy versus x is is shown in Figure 2. No friction involves throughout the path. The ball has a total energy of 60.0 J and the zero potential reference is at x = 0 m. [Answer in 3 significant figures] F, versus x 30 25 20 15 10 0. -5 0 2. 4 5 -6- 8 - 6. 10 -10 -15 -20 -25 -30 -35 -40 -45 -50 -55 -60 x (m) Figure 1 Conservative force versus position Potential energy versus X 1. 1. 1. 3. (N) *)
A pendulum consists of a 1.2 kg stone swinging on a 4.2 m string of negligible mass. The stone has a speed of 8.3 m/s when it passes its lowest point. (a) What is the speed when the string is at 56" to the vertical? (b) What is the greatest angle with the vertical that the string will reach during the stone's motion? (c) If the potential energy of the pendulum-Earth system is taken to be zero at the stone's lowest point, what is the total mechanical energy of the system? (a) Number i Unit (b) Number i Unit (c) Number i Unit
A ball moves on a frictionless track as shown below. The horizontal plane passing through the initial point O is taken as a reference for the gravitational potential energy (At O, PEg =0). Assume that the speed of the ball at point O is v_O = 2 m/s and the ball stops at point B. The height of point B is equal to: hg 20 cm 5 cm 45 cm 6 p B PEg=0
The figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA-15.0J, Us - 35.0 J and Uc-45.0 J. The particle is released at x -4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x -1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x- 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x - 4.50 m at speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m? (0)2 Ucr UB UA 2 (a) Number (b) Number 10 4 x (m) (c) positive (+x) (e)…
The figure here shows a plot of potential energy U versus position x of a 0.877 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA = 15.0 J, Ug = 35.0 J and Uc = 45.0 J. The particle is released at x = 4.50 m with an initial speed of 7.39 m/s, headed in the negative x direction. (a) If the particle can reach x = 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x = 4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x = 4.50 m at speed 7.39 m/s. (d) If the particle can reach x = 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x = 5.00 m? Uc UB UA 4. x (m) (a) Number | Unit (b) Number Unit (c) (d) Number…