A connected simple graph G has 202 edges. (a) Determine the minimum and maximum number of vertices it can have. Explain your reasoning. (b) Can G be self-complementary? Why or why not?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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[Graph Theory] How do you solve a) and b)?

For a), would the maximum number of vertices be 202 if you made a cycle graph where every pair of vertices has at most one edge? How would you calculate the minimum number of vertices?

For b), is G self-complementary?

Definition 5.4.15. Graph Complement. Let G = (V,E) be a simple graph.
We define its complement G to be the graph on the same vertex set V(G), and
with edge set
E' = {(u, v) E V × V : (u, v) £ E},
that is, (u, v) is an edge in G if and only if it was not an edge in G.
Example 5.4.16. A Graph and its Complement. A graph G (red) and its
complement G (blue) are shown below.
5
3 6
3 6
3
1
2
1
2
G
G
Transcribed Image Text:Definition 5.4.15. Graph Complement. Let G = (V,E) be a simple graph. We define its complement G to be the graph on the same vertex set V(G), and with edge set E' = {(u, v) E V × V : (u, v) £ E}, that is, (u, v) is an edge in G if and only if it was not an edge in G. Example 5.4.16. A Graph and its Complement. A graph G (red) and its complement G (blue) are shown below. 5 3 6 3 6 3 1 2 1 2 G G
A connected simple graph G has 202 edges.
(a) Determine the minimum and maximum number of vertices it can have. Explain your reasoning.
(b) Can G be self-complementary? Why or why not?
Transcribed Image Text:A connected simple graph G has 202 edges. (a) Determine the minimum and maximum number of vertices it can have. Explain your reasoning. (b) Can G be self-complementary? Why or why not?
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