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A cone-shaped paper cup is being produced such that it holds 100 cm³ of liquid. The material that will be used to produce the cups cost 0.25 cents per cm². Let the cost be a function of r and the slant height of the cup be defined as s=√²+h². Which of the following equations will help to determine the lowest cost? (Hint: the base of the cup would not be included, since it is open.) O 290000 + (0.25zr√². (0.25x² +0.25m² d 0 0.25%(*√²300) )=0 90000 2,4 0 0.25%(x²+xr √² + 300 -) = 0 )=0

A cone-shaped paper cup is being produced such that it holds 100 cm³ of liquid. The material that will be used to produce the cups cost 0.25 cents per cm². Let the cost be a function of r and the slant height of the cup be defined as s=√²+h². Which of the following equations will help to determine the lowest cost? (Hint: the base of the cup would not be included, since it is open.) O 290000 + (0.25zr√². (0.25x² +0.25m² d 0 0.25%(*√²300) )=0 90000 2,4 0 0.25%(x²+xr √² + 300 -) = 0 )=0

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A cone-shaped paper cup is being produced such that it holds 100 cm³ of liquid. The material that will be used to produce the cups cost 0.25 cents per cm². Let the cost be a function of r and the slant height of the cup be defined as s=√√r²+h². Which of the following equations will help to determine the lowest cost? (Hint: the base of the cup would not be included, since it is open.) O d (0.25zr r²+ -) = 0 90000 2.4 O -(0.25r² +0.25πrr² + 0.25 (Tr√² +300) -) = 0 dr лr² O 0.25 O 0.25 0.25 € (Tr² + 2 + πr. /r². Fr + dr 300 ær 90000 ²,4 -) = 0 -) = 0
Transcribed Image Text:A cone-shaped paper cup is being produced such that it holds 100 cm³ of liquid. The material that will be used to produce the cups cost 0.25 cents per cm². Let the cost be a function of r and the slant height of the cup be defined as s=√√r²+h². Which of the following equations will help to determine the lowest cost? (Hint: the base of the cup would not be included, since it is open.) O d (0.25zr r²+ -) = 0 90000 2.4 O -(0.25r² +0.25πrr² + 0.25 (Tr√² +300) -) = 0 dr лr² O 0.25 O 0.25 0.25 € (Tr² + 2 + πr. /r². Fr + dr 300 ær 90000 ²,4 -) = 0 -) = 0
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