A condenser having a capacity of 50muF is charged to a potential of 200 V. If the area of each plate of the condenser is 10cm^(2) and the distance between the plates is 0.1 mm. The energy per unit volume of the field between the plates is.
Q: Electrons accelerate at a high rate from the negative to the positive electrode of an x-ray tube,…
A:
Q: A Van de Graaff generator has a 0.250 m diameter metal sphere that produces a voltage of 100 kV near…
A: Given Diameter = 0.250 m Voltage = 100 kV We have to calculate the excess charge on the surface.
Q: scientist is busy at work in his lab trying to calculate potential differences. He observes a charge…
A:
Q: A gold(III) ion is accelerated by the electric field created between two parallel plates separated…
A: As charge is placed in an electric field due to electric force there will be work done on the…
Q: A parallel plate system has a plate separation distance of 18.2 cm. The plates are connected to a…
A:
Q: A parallel-plate capacitor has a capacitance of 680 pF, a plate area of 580 cm², and a mica…
A: Given data, Capacitance C=680 pF Dielectric K=5.4 Voltage V=26 V Area=580 cm2
Q: The two plates of a parallel-plate capacitor each have area1.20 m2, are 4.50 mm apart, and initially…
A: Given: The area of the plates is 1.20 m2. The distance between the plates is 4.50 mm. The power…
Q: One capacitor is charged until its stored energy is 5.0 J. A second uncharged capacitor is then…
A: Initial stored energy U = 5 J U = 12q2C Where q = total charge C = capacitance of the capacitor
Q: An old CRT monitor is being demonstrated. You know that a beam of electrons is directed at the…
A: The potential difference across the electric field, The velocity of the electron, The distance…
Q: A uniform electric field of magnitude 277V/m is directly in the positive x-direction. A 1.33E-5C…
A:
Q: Two plates separated by a distance d = 14.3 mm are charged to a potential difference V = 7.25 V. A…
A: Separation distance between the plates, d = 14.3 mm = 0.0143 mPotential difference, V = 7.25 VForce,…
Q: Problem 4: An electron is initially at rest in a uniform electric field having a strength of 1.8 ×…
A: Given information: The strength of the electric Field (E) = 1.8×106 V/m Part a: The distance…
Q: Considering electron and proton as two charged particles separated by d=5.1 x 10-¹1 m calculate the…
A: Given data, separation, d= 5.1×10-11 m Charge of proton, q1= 1.6×10-19 C Change of electron, q2= -…
Q: In a uniform electric field, if a negatively charged particle is moving in the direction of the…
A: Answer= Yes, A negative charge moving in a uniform field Assuming that the negative charge moves…
Q: The electric field strength between two parallel conducting plates separated by 10.00 cm is 7.50×104…
A:
Q: - An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of…
A:
Q: A potential difference of 2-V is applied between two large parallel metal plates separated by a…
A: Write the given values with the suitable variables. V=2 Vd=2 mm=2×10-3 m Here, V is the potential…
Q: An electric dipole consists of two particles, each with mass 16 Dalton, and charges +2e. The…
A: Mass of each particle m = 16 dalton = 16 × 1.66 × 10- 27 kg = 2.66 × 10- 26 kg Momentum transferred…
Q: A uniform electric field of magnitude 250. V/m is directed in the positive xdirection. A 12.0-μC…
A:
Q: A 2.12 nF parallel plate capacitor has plates of area 0.0049 m2 and plate separation 0.01 cm. What…
A: C=ϵo(A/d) ϵo= Cd/A
Q: Oppositely charged parallel plates are separated by 6.28 mm. A potential difference of 600 V exists…
A: Given values:Potential difference between the plates, V = 600 VDistance between the plates, d = 6.28…
Q: A parallel-plate capacitor has a capacitance of 630 pF, a plate area of 420 cm?, and a mica…
A: Given Capacitance, C= 630 pF Area of plates A= 420 cm2…
Q: droplet is suspended between oppositely charged, horizontal parallel plates near Earth's surface.The…
A:
Q: A capacitor is constructed with a plate separation of 0.0003755m and the electric field between the…
A:
Q: Two parallel plates separated by 2.4 mm form a capacitor. The top plate has a voltage of -3 bolts,…
A: Inside of a parallel plate capacitor, the electric field is constant. And it is given by V=EdE=Vd
Q: Oppositely charged parallel plates are separated by 5.35 mm. A potential difference of 500 V exists…
A: Given: The separation between plates is 5.35 mm. The potential difference is 500 V.
Q: The potential difference between two parallel plates is 598 V. An alpha particle with mass of…
A:
Q: How strong is the electric field in N/C between two parallel plates (5.0000x10^0) mm apart if the…
A:
Q: how far was it raised or lowered?
A:
Step by step
Solved in 2 steps
- A capacitor is composed of two metal plates. The two plates have the dimensions L = 0.11 m and W = 0.56 m. The plates have a distance between them of d = 0.1 m, and are parallel to each other. Part (a) The plates are connected to a battery and charged such that the first plate has a charge of q. Write an expression for the magnitude of the electric field, |E|, halfway between the plates. Part (b) Input an expression for the magnitude of the electric field, |E2|, just in front of plate two. Part (c) If plate two has a total charge of q = -1 mC, what is its charge density, σ, in C/m2?A bare helium nucleus has two positive charges and a mass of 6.64 x 10-27 kg. (a) Calculate its kinetic energy in joules at 8.40% of the speed of light. 2.34e-9 What is the basic definition of kinetic energy? J (b) What is this in electron volts? 1.46e10 What is the definition of an electron volt? ev (c) What voltage would be needed to obtain this energy? 7.3e9 Did you consider applying the conservation of energy principle? VA helium-filled balloon with a 14.5 nC charge rises 290 m above Earth’s surface. By how much does the electrical potential energy change if Earth’s electric field is −105 N/C?
- Two plates separated by a distance d = 15.3 mm are charged to a potential difference V = 7.25 V. A constant force F = 8.31 N pushes a –8.30 mC charge from the positively charged plate to the negatively charged plate. Calculate the change in the kinetic energy AK, potential energy AU, and total energy AE of the charge as it travels from one plate to the other. Assume the initial speed of the charge is 0. AK = AU =An ideal air-filled parallel-plate capacitor with horizontal plates has a plate separation of 7.30 cm. If the potential difference between the plates is 1,307 V, what is the magnitude of the electric field between the plates?A parallel plate capacitor has a potential difference between it's plates of 1.2 V and a plate separation distance of 2.0 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.3 is inserted between the plates?