A concentration cell based on the following half reaction at 313 K Ag* + e¯ → Ag; SRP=0.80V is made from two 1.00 L solutions of Ag*, 1.32 M and 0.269 M; two 100.0 g pieces of Ag metal, a wire, and a salt bridge. Under these conditions the potential of the cell is 0.042902 V. How much Ag metal will need to be oxidized for the potential of the cell to decrease by 0.026938 V? Give your answer to 3 decimal places. 0.1 e x0% (6)

A concentration cell based on the following half reaction at 313 K Ag* + e¯ → Ag; SRP=0.80V is made from two 1.00 L solutions of Ag*, 1.32 M and 0.269 M; two 100.0 g pieces of Ag metal, a wire, and a salt bridge. Under these conditions the potential of the cell is 0.042902 V. How much Ag metal will need to be oxidized for the potential of the cell to decrease by 0.026938 V? Give your answer to 3 decimal places. 0.1 e x0% (6)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

A concentration cell based on the following half reaction at 313 K
Ag* + e¯ → Ag; SRP =0.80V
is made from two 1.00 L solutions of Agt, 1.32 M and 0.269 M; two 100.0 g pieces of Ag metal, a wire, and a
salt bridge. Under these conditions the potential of the cell is 0.042902 V. How much Ag metal will need to be
oxidized for the potential of the cell to decrease by 0.026938 V?
Give your answer to 3 decimal places.
(9)
0.1
X 0%
This question is complete and cannot be answered again.

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