A computer repair shop has estimated the probability that a computer sent to the shop has a bad modem is the probability that the computer has a bad CPU is and the probability that it has a bad drive s. If we assume that modems, CPUS, and drives are independent, find the probability of the following. (Enter your probabilities as fractions.) (a) A modem, CPU, and a drive in a computer sent to the shop are bad. 1/64 (b) Only a modem and a CPU in a computer sent to the shop are bad. 3/64 (c) None of the three parts (modem, CPU, or drive) is bad. 21/64 Additional Materials

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**Problem: Probability and Independence of Computer Parts**

A computer repair shop has estimated the probability that a computer sent to the shop has a bad modem is \( \frac{1}{2} \), the probability that the computer has a bad CPU is \( \frac{1}{8} \), and the probability that it has a bad drive is \( \frac{1}{5} \). 

If we assume that modems, CPUs, and drives are independent, find the probability of the following. (Enter your probabilities as fractions.)

a) A modem, CPU, and a drive in a computer sent to the shop are bad.  
\[ \frac{1}{64} \] ❌

b) Only a modem and a CPU in a computer sent to the shop are bad.  
\[ \frac{3}{64} \] ❌

c) None of the three parts (modem, CPU, or drive) is bad.  
\[ \frac{21}{64} \] ❌

---

**Explanation:**
This problem involves calculating probabilities under the assumption that the states of the modem, CPU, and drive are independent events. We calculate the probability of combined events using the product of individual probabilities for independent events.

- For part (a), multiply the individual probabilities:  
  \(\frac{1}{2} \times \frac{1}{8} \times \frac{1}{5} = \frac{1}{80}\).

- For part (b), calculate the probabilities assuming only the modem and CPU are bad. This involves:
  \(\frac{1}{2} \times \frac{1}{8} \times \left(1 - \frac{1}{5}\right) = \frac{1}{16} \).

- For part (c), calculate the probability that none of the parts are bad:  
  \((1 - \frac{1}{2}) \times (1 - \frac{1}{8}) \times (1 - \frac{1}{5}) = \frac{7}{40}\).

Note that the answers provided in the problem attempt are incorrect, as indicated by the red crosses. Correct calculations should be aligned with the explanation given above.
Transcribed Image Text:**Problem: Probability and Independence of Computer Parts** A computer repair shop has estimated the probability that a computer sent to the shop has a bad modem is \( \frac{1}{2} \), the probability that the computer has a bad CPU is \( \frac{1}{8} \), and the probability that it has a bad drive is \( \frac{1}{5} \). If we assume that modems, CPUs, and drives are independent, find the probability of the following. (Enter your probabilities as fractions.) a) A modem, CPU, and a drive in a computer sent to the shop are bad. \[ \frac{1}{64} \] ❌ b) Only a modem and a CPU in a computer sent to the shop are bad. \[ \frac{3}{64} \] ❌ c) None of the three parts (modem, CPU, or drive) is bad. \[ \frac{21}{64} \] ❌ --- **Explanation:** This problem involves calculating probabilities under the assumption that the states of the modem, CPU, and drive are independent events. We calculate the probability of combined events using the product of individual probabilities for independent events. - For part (a), multiply the individual probabilities: \(\frac{1}{2} \times \frac{1}{8} \times \frac{1}{5} = \frac{1}{80}\). - For part (b), calculate the probabilities assuming only the modem and CPU are bad. This involves: \(\frac{1}{2} \times \frac{1}{8} \times \left(1 - \frac{1}{5}\right) = \frac{1}{16} \). - For part (c), calculate the probability that none of the parts are bad: \((1 - \frac{1}{2}) \times (1 - \frac{1}{8}) \times (1 - \frac{1}{5}) = \frac{7}{40}\). Note that the answers provided in the problem attempt are incorrect, as indicated by the red crosses. Correct calculations should be aligned with the explanation given above.
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