A compound was decomposed and determined to be 51.27 % C, 7.75% H and 40.98 %O  by mass.  What is the subscript for C in the empirical formula for this compound?

Q: A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is…

A: Given,Percent of B in the compound = 40.28 %Percent of N in the compound = 52.20 %Percent of H in…

Q: The percent composition by mass of an unknown chlorinated hydrocarbon was found to be 37.83% C,…

A:

Q: Nitroglycerin contains 15.87% C, 2.22% H, 18.50% N, and 63.41% O by mass. Determine the empirical…

A:

Q: A particular compound is comprised only of the elements C, H, N, and Cl. Combustion analysis of…

A: Given that: Total mass of sample = 14.30 g Mass of CO2 = 31.22 g Mass of H2O = 6.764 g Mass % of N=…

Q: An ionic compound was formed by combining 8.289 g of copper (Cu) with 1.218 g of nitrogen (N). What…

A: Given that, Mass of copper Cu = 8.289 g Moles of Cu in 8.289 g = 8.289 g/63.546 g/mol = 0.13044 mol…

Q: A molecule is found to contain 47.35% by mass C, 10.60% by mass H, and 42.05% by mass O. What is the…

A: The solution to the empirical formula of the compound is attached below.

Q: An organic compound used as a food additive in beverages and baking powders, is composed of 41.39%…

A: Given  % C  = 41.39 % H = 3.47  % O = 100 -( 41.39 + 3.47 ) %         = 55.14 %  Empirical Formula =…

Q: What is the empirical formula of the compound containing 55.8% carbon, 7.0% hydrogen, and 37.2%…

A: Given is, 55.8% carbon, 7.0% hydrogen, and 37.2% oxygen by mass

Q: 0.5998 -g sample of a new compound has been analyzed and found to contain the following masses of…

A: The question is based on elemental analysis. we have been given mass of the elements. We have to…

Q: A 57.00g sample is composed of 69.61% Barium, 6.093% Carbon, and 24.28% Oxygen. What is the…

A: Empirical Formula  of the compound is BaCO3

Q: A sample compound is 46.7% oxygen, 51.7% chlorine, and 1.5% hydrogen. What is the empirical formula…

A:

Q: A substance was found to contain 65.95% barium and 34.05% chlorine by mass upon analysis. What is…

A: Given that mass percent of barium is 65.95 % and mass percent of chlorine is 34.05%.

Q: The compound adrenaline contains 56.79% C, 6.56% H, 28.37% O, and 8.28% N by mass. What is the…

A: Let the mass of adrenaline be 100 g.Thus, mass of:C = 56.79 gH = 6.56 gO = 28.37 gN = 8.28 gThus,…

Q: will

A:

Q: An organic compound contains 24.24 % Carbon, 4.04 % Hydrogen, and 71.72 % Chlorine. What is its…

A: Given, Mass % of carbon (C) = 24.24 % = 24.24 g Mass % of hydrogen (H) = 4.04 % = 4.04 g Mass % of…

Q: A 0.5998-g sample of a new compound has been analyzed and found to contain the following masses of…

A: Given, mass of sample of compound = 0.5998 g The sample contains, mass of Carbon (C) = 0.2322 g mass…

Q: A compound is 54.53% carbon, 9.15% hydrogen, and 36.32% oxygen by mass. What is its empirical…

A: This question belongs to Mole concept. we have used formula  Mass % of an element = Mass of that…

Q: Potassium bromate is a colorless , crystalline substance whose composition is 23.4 % K , 47.8 % Br ,…

A: An empirical formula gives the smallest whole number ratio of different elements present in the…

Q: what is the empirical formula of a compound found to contain 52.13 % carbon, 13.15 % hydrogen, and…

A: Given : Mass percent of C = 52.13 % Mass percent of H = 13.15 %  And mass percent of O = 34.72 %…

Q: A compound is 7.7% (by mass) hydrogen and 92.7 % carbon. It has a molecular weight of 52 g/mole.…

A: Empirical formula are the formula which represent simplest ratio of an element present in a given…

Q: In a first expirement, a compound is analyzed and found to contain 85.63% C and 14.37% hydrogen by…

A: 1. atom % in samp;e mole Mole ratio (divided by smallest number of moles) C 85.63 85.63 /12 =…

Q: What is the empirical formula of a compound that is 54.5% C, 9.2% H, and 36.3% O by mass?

A: Assuming the empirical formula is CxHyOz  hence the ration = C : H : O = x : y : z = mole ration of…

Q: Two compounds have the same composition: 92.25% C and 7.75% H . Obtain the empirical formula…

A: Given data, C = 92.25% H = 7.75% The molecular weight of one of the compound = 26.02 amu The…

Q: experiment, 3.15 g of this compound  was combusted to produce 5.69 g of CO2 , 2.72 g H2O and 0.734 g…

A: Moles of C = 5.69/44 = 0.129 mol Mass of C = 0.129×12 = 1.55 g Moles of H = 2.72×2/18 = 0.302 mol…

Q: An organic compound contains only carbon, hydrogen, nitrogen, and oxygen. It is 61.71% C, 4.03% H,…

A:

Q: A compound is found to contain 26.96 % sulfur, 13.45 % oxygen, and 59.59 % chlorine by mass. What…

A: empirical formula - formula which gives us the simplest positive integer ratio proportion of the…

Q: A compound is composed of elements C, H, and N. A 12.075-mg sample of the unknown compound was…

A:

Q: 8. An explosive has the following composition by mass: 15.87% Carbon, 2.22% Hydrogen, 18.5% Nitrogen…

A: Given : Molecule which contains only H, C, N and O. Mass percent of C = 15.87 % Mass percent of H =…

Q: a) A compound is found to contain 52.13 % carbon, 13.15 % hydrogen, and 34.72 % oxygen by mass.What…

A: (a) Given: Mass percent composition of hydrogen is 13.15% Mass percent composition of carbon is…

Q: g nitrogen, 1) A compound is found to have 0.640 g oxygen. What is its empirical formula? g…

A: To derive the empirical formula of a compound, it is important to convert the weight of the…

Q: A compound is composed of 27.29% C and 72.71% O by mass. What is its empirical formula?

A: The empirical formula shows the kind and proportions of atoms in a substance in its simplest form.…

Q: A compound is composed of elements C, H, and N. A 4.200 mg sample of the unknown compound was…

A: The percentage of carbon and hydrogen can be calculated by using mass of CO2 and H2O produced by the…

Q: An iron-containing compound is 20.1% Fe, 11.5% S, 63.3% O, and 5.1% H. What is the empirical formula…

A: Given,The elemental analysis report gives the 20.1% Fe, 11.5 % S, 63.3 % oxygen, and 5.1% hydrogen.…

Q: A student obtained the following mass composition of a compound: C: 50.89%. H:8.51%. O: 40.60% What…

A:

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.