World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter6: Chemical Composition
Section: Chapter Questions
Problem 33A
Related questions
Question
A compound is 22.76% Carbon, 68.30% Boron and 8.93% Hydrogen
by mass. What is this compound’s empirical formula?
Expert Solution
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Step 1
The given percentage of different elements firstly changed into moles by deviding it by atomic masses , then devide all moles by smallest value, we can get empirical formula of compound.
Carbon - 22.76/12 = 1.896
Boron - 68.30/11 = 6.201
Hydrogen - 8.93/1 = 8.93
Now, devide all by lowest value 1.896 -
Carbon - 1.896/1.896 = 1
Boron - 6.201/1.896 = 3.33
Hydrogen - 8.93/1.896 = 4.71
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