A compound decomposes by a first-order reaction. If the concentration of the compound is \(4.01 \times 10^{-2} \, M\) after 61 seconds, when the initial concentration was \(5.50 \times 10^{-2} \, M\), what is the concentration of the compound after 88 seconds?Concentration = \(\boxed{\,}\) \(M\)

Initial concentration of the compound [A0] = 5.50 x 10-2 M Concentration of the compound after 61…

A compound decomposes by a first-order reaction. If the concentration of the compound is 4.01 × 10-2 M after 61 s, when the initial concentration was 5.50 x 10-2 M, what is the concentration of the compound after 88 s? Concentration M

A compound decomposes by a first-order reaction. If the concentration of the compound is 4.01 × 10-2 M after 61 s, when the initial concentration was 5.50 x 10-2 M, what is the concentration of the compound after 88 s? Concentration M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A compound decomposes by a first-order reaction. If the concentration of the compound is \(4.01 \times 10^{-2} \, M\) after 61 seconds, when the initial concentration was \(5.50 \times 10^{-2} \, M\), what is the concentration of the compound after 88 seconds?

Concentration = \(\boxed{\,}\) \(M\)

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