A composite assembly of length, L= 350 mm, consisting of a steel [G- 77 GPa) core (2) connected by rigid plates at the ends of an aluminum [G- 31 GPa) tube (1) is shown. The aluminum tube has outside diameter D; - 50 mm and inside diameter dy 30 mm. The solid steel core has diameter d,- 20 mm. The allowable shear stress of aluminum tube (1) is (ral = 85 MPa, and the allowable shear stress of steel core (2) is (rallow ) = 135 MPa. Determine (a) the allowable torque T that can be applied to the composite shaft. (b) the corresponding torques produced in tube (1) and core (2). (c) the angle of twist produced by the allowable torque T.
A composite assembly of length, L= 350 mm, consisting of a steel [G- 77 GPa) core (2) connected by rigid plates at the ends of an aluminum [G- 31 GPa) tube (1) is shown. The aluminum tube has outside diameter D; - 50 mm and inside diameter dy 30 mm. The solid steel core has diameter d,- 20 mm. The allowable shear stress of aluminum tube (1) is (ral = 85 MPa, and the allowable shear stress of steel core (2) is (rallow ) = 135 MPa. Determine (a) the allowable torque T that can be applied to the composite shaft. (b) the corresponding torques produced in tube (1) and core (2). (c) the angle of twist produced by the allowable torque T.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A composite assembly of length, L= 350 mm, consisting of a steel [G- 77 GPa) core (2) connected by rigid plates at the ends of an
aluminum [G - 31 GPa) tube (1) is shown. The aluminum tube has outside diameter D; - 50 mm and inside diameter di = 30 mm.
The solid steel core has diameter dz = 20 mm. The allowable shear stress of aluminum tube (1) is (Falw ) = 85 MPa, and the
allowable shear stress of steel core (2) is (rallow 2 = 135 MPa. Determine
(a) the allowable torque T that can be applied to the composite shaft.
(b) the corresponding torques produced in tube (1) and core (2).
(c) the angle of twist produced by the allowable torque T.
(1)
d2
di
DI
B
L.
Calculate the polar moment of inertia, J1. of the aluminum tube.
(10) mm.
Answer: J
5.3407075
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